a = [1,0,1]
b = [101101, 0101100, 1011001101, 11000111, 1010110]
i = 0
j = 0
c = []
x = 0
d = []
while x < 5
c.push b[i].to_s.split('')
p c
x = x +1
end
while i < 5
e = c[i].length
e = e + 1
while j < e
d[i][j] = a[i][j % 3] ^ b[i][j]
puts d
j = j + 1
end
i = i + 1
end
==> Resolv error line : d[i][j] = a[i][j % 3] ^ b[i][j]
====> __.rb:18: undefined method `[]=' for nil:NilClass (NoMethodError)
我看不到..
由于
答案 0 :(得分:2)
如果您想使用d[i][j]
,则应创建2维:
...
d[i] = []
while j < e
d[i][j] = a[i][j % 3] ^ b[i][j]
puts d
j = j + 1
end
...
但无论如何这都是一个奇怪的代码。如果a[i][j % 3]
是一维数组,为什么使用a
?
答案 1 :(得分:0)
您的变量d
只有一个维度,而在第二个while
您尝试分配两个维度值d[i][j]
。要解决此问题,请将其他字符串添加到while:
d[i] |= []
while j < e
d[i][j] = a[i][j % 3] ^ b[i][j]
puts d
j = j + 1
end