Question

我的代码有效，只有一个问题。该代码用于在两个用户输入之间打印数字。代码的该部分有效，但是，如果第一个数字大于第二个数字，则意味着不打印并再次询问。到那时为止，所有内容都可以使用，但是如果第一个数字大于第二个，控制台和代码就结束了，我不知道为什么吗？你们能帮我解释我做错了吗？谢谢！这是我的代码：

public static void main(String[] args) {
    Scanner reader = new Scanner(System.in);

    int higherNum, lowerNum;

    System.out.print("First: ");
    lowerNum=Integer.parseInt(reader.nextLine());

    System.out.print("Second: ");
    higherNum=Integer.parseInt(reader.nextLine());

    while (higherNum>=lowerNum){
        if (lowerNum>higherNum){
            System.out.print("Sorry, you put your first number higher than your second, please make your first number a smaller number than your second. "); // this does not print 
        }
    }

    System.out.println(lowerNum++);
}

Answer 1

仅当upperNum> = lowerNum时才开始循环，这意味着循环内的if条件永远不会成立。

要实现输出，您应该执行以下操作。

while (lowerNum>higherNum ){
            System.out.print("Sorry, you put your first number higher than your second,   please make your first number a smaller number than your second. "); // this does not print

            System.out.print("First: ");
            lowerNum=Integer.parseInt(reader.nextLine());

            System.out.print("Second: ");
            higherNum=Integer.parseInt(reader.nextLine());

        }

        while(lowerNum <= higherNum) {
            System.out.println(lowerNum++);
        }

Answer 2

我建议您先使用if条件：

if (lowerNum>higherNum){
    System.out.print("Sorry, you put your first number higher than your second, please make your first number a smaller number than your second. ");
} else{
    while (higherNum>=lowerNum){
        System.out.println(lowerNum++);
    }
}

之所以发生这种情况，是因为如果lowerNum大于higherNum，则由于错误消息位于while循环内，因此while条件将导致false并且不会输出任何内容。

Answer 3

您应该早于此。我在修复其他问题。

public static void main(String[] args) {

    Scanner reader = new Scanner(System.in);
    int higherNum = 0, lowerNum = 1;

    while(lowerNum>=higherNum){

        System.out.print("First: ");
        lowerNum=Integer.parseInt(reader.nextLine());

        System.out.print("Second: ");
        higherNum=Integer.parseInt(reader.nextLine());

        if(lowerNum>=higherNum){

            System.out.println("Sorry, you put your first number higher than your second, please make your first number a smaller number than your second. ");

        } else {

            while(lowerNum<higherNum-1){
                System.out.println(++lowerNum);
            }

        }
    }
}

Answer 4

您可以使用重新启动过程的方法来为数字输入。递归选项将有助于解决该问题。

公共无效TakeNumbers（）{ 扫描仪阅读器=新的Scanner（System.in）;

int higherNum, lowerNum;

System.out.print("First: ");
lowerNum=Integer.parseInt(reader.nextLine());

System.out.print("Second: ");
higherNum=Integer.parseInt(reader.nextLine());

 if (lowerNum>higherNum){
        System.out.print("Sorry, you put your first number higher than your second, please make your first number a smaller number than your second. ");

TakeNumbers();

System.out.println(lowerNum++);

}

public static void main（String [] args）{

TakeNumbers();

}

Answer 5

只需在下面的链接中，它将在循环中打印以进行确认

https://www.sanfoundry.com/java-program-check-given-number-perfect-number/

“如果”语句将不会循环打印

5 个答案: