我有两列布局,左边一个元素,右边两个。
如何使右列中的最后一个元素相对于左列的底部对齐?
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no">
<meta name="description" content="">
<meta name="author" content="">
<title>Bare - Start Bootstrap Template</title>
<!-- Bootstrap core CSS -->
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/css/bootstrap.min.css" integrity="sha384-Vkoo8x4CGsO3+Hhxv8T/Q5PaXtkKtu6ug5TOeNV6gBiFeWPGFN9MuhOf23Q9Ifjh" crossorigin="anonymous">
</head>
<body>
<!-- Navigation -->
<nav class="navbar navbar-expand-lg navbar-dark bg-dark static-top">
<div class="container">
<a class="navbar-brand" href="#">Start Bootstrap</a>
<button class="navbar-toggler" type="button" data-toggle="collapse" data-target="#navbarResponsive" aria-controls="navbarResponsive" aria-expanded="false" aria-label="Toggle navigation">
<span class="navbar-toggler-icon"></span>
</button>
<div class="collapse navbar-collapse" id="navbarResponsive">
<ul class="navbar-nav ml-auto">
<li class="nav-item active">
<a class="nav-link" href="#">Home
<span class="sr-only">(current)</span>
</a>
</li>
<li class="nav-item">
<a class="nav-link" href="#">About</a>
</li>
<li class="nav-item">
<a class="nav-link" href="#">Services</a>
</li>
<li class="nav-item">
<a class="nav-link" href="#">Contact</a>
</li>
</ul>
</div>
</div>
</nav>
<!-- Page Content -->
<div class="container-fluid">
<div class="row">
<div class="col-7">
<div class="card card-block">
<h3>Column 1</h3>
<br />
<br />
<br />
<p>..end of content</p>
</div>
</div>
<div class="col-5">
<div class="row no-gutters">
<div class="col-12">
<div class="card card-block">
<h3>Column 2</h3>
</div>
</div>
<div class="col-12 align-self-end">
<div class="card card-block">
<h3>Column 3</h3>
</div>
</div>
</div>
</div>
</div>
</div>
<!-- Bootstrap core JavaScript -->
<script src="https://code.jquery.com/jquery-3.4.1.slim.min.js" integrity="sha384-J6qa4849blE2+poT4WnyKhv5vZF5SrPo0iEjwBvKU7imGFAV0wwj1yYfoRSJoZ+n" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js" integrity="sha384-Q6E9RHvbIyZFJoft+2mJbHaEWldlvI9IOYy5n3zV9zzTtmI3UksdQRVvoxMfooAo" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/js/bootstrap.min.js" integrity="sha384-wfSDF2E50Y2D1uUdj0O3uMBJnjuUD4Ih7YwaYd1iqfktj0Uod8GCExl3Og8ifwB6" crossorigin="anonymous"></script>
</body>
</html>
谢谢您的帮助!
答案 0 :(得分:2)
通过将.align-items-end
添加到父行,它会将各列垂直对齐到其底部。
如果您想在顶部放置第3列,但保留第4列的当前位置,我建议您看一下一个名为eqHeight的jQuery库。这样,您就可以将父列(col-7
和col-5
)拉伸到相同的高度,此后,第3列应在第1列的顶部。
<!-- Page Content -->
<div class="container-fluid">
<div class="row align-items-end">
<div class="col-7">
1<br>
<br>
<br>
2
</div>
<div class="col-5">
<div class="col-12">
3
</div>
<div class="col-12 align-self-end">
4
</div>
</div>
</div>
</div>
答案 1 :(得分:1)
library(geosphere)
library(dplyr)
person_location <-
structure(list(id = c(1, 2, 3, 4, 5),
longitude = c(-76.67707, -76.44519, -76.69402, -76.68936, -76.58341),
latitude = c(39.399754, 39.285084, 39.36958, 39.369907, 39.357994)),
class = "data.frame", row.names = c(NA, -5L))
building_location <-
structure(list(id_building = c(1, 2, 3, 4, 5, 6, 7, 8, 9),
longitude_building = c(-76.624393, -76.457246, -76.711729, -76.631249, -76.566742, -76.683106, -76.530232, -76.598582, -76.691287),
latitude_building = c(39.246464, 39.336996, 39.242936,39.289103, 39.286271, 39.35447, 39.332398, 39.344642, 39.292849)),
class = "data.frame", row.names = c(NA, -9L))
all_locations <- merge(person_location, building_location, by=NULL)
all_locations$distance <- distHaversine(
all_locations[, c("longitude", "latitude")],
all_locations[, c("longitude_building", "latitude_building")]
)
closest <- all_locations %>%
group_by(id) %>%
filter( distance == min(distance) ) %>%
ungroup()
Created on 2020-01-07 by the reprex package (v0.3.0)
Why not use different row for 1 - 3 and 2 - 4.
Because you have using bootstrap grid system.
7 col - 5 col
-------------
答案 2 :(得分:-1)
这可能是您想要的:
<div class="row">
<div class="col-md-6">
1
</div>
<div class="col-md-6">
3
</div>
</div>
<div class="row">
<div class="col-md-6">
2
</div>
<div class="col-md-6">
4
</div>
</div>
OR
<div class="row">
<div class="col-md-6">
1
</div>
<div class="col-md-6">
<div class="row">
<div class="col-md-12">
2
</div>
<div class="col-md-12">
3
</div>
</div>
</div>
</div>
答案 3 :(得分:-2)
<div class="col-5">
<row class="no-gutters">
<div class="col-lg-12">
3
</div>
<div class="col-lg-12">
4
</div>
</row>
</div>
在任何屏幕尺寸下都将全角显示。