温度转换器不给出输出

时间:2011-05-11 09:38:41

标签: iphone

我已为iphone编写了温度转换代码,但它无法正常工作,也没有给出任何错误请帮助

界面部分

#import <UIKit/UIKit.h>

float n ;
float k;



@interface farh_celcius_conv_AppDelegate : NSObject <UIApplicationDelegate> {
    UIWindow *window;
    UILabel *display;
    IBOutlet UITextField *farhenite;
    IBOutlet UIButton *convert;

}


-(IBAction) convert; 


@property (nonatomic, retain) IBOutlet UIWindow *window;
@property (nonatomic, retain) IBOutlet UILabel *display;
@property (nonatomic, retain) IBOutlet UITextField *farhenite;
@property (nonatomic, retain) IBOutlet UIButton *convert;
@end

实施部分

#import "farh_celcius_conv_AppDelegate.h"


@implementation farh_celcius_conv_AppDelegate


@synthesize window,display,farhenite;





-(IBAction) convert  {

    NSString *str = [NSString text];

    float n = [str floatValue];


      k = (n - 32)*(5/9);



    [display setText:[NSString stringWithFormat:@"%f",k]];  

}

- (void)applicationDidFinishLaunching:(UIApplication *)application {    

    // Override point for customization after application launch
    [window makeKeyAndVisible];
}


- (void)dealloc {
    [window release];
    [super dealloc];
}


@end

5 个答案:

答案 0 :(得分:1)

如果你想转换在textField中输入的值,那么方法应该是这样的

-(IBAction) convert  {

    NSString *str = yourTextField.text; // In your case farhenite i guess

    float n = [str floatValue];


      k = (n - 32)*(5/9);



    [display setText:[NSString stringWithFormat:@"%f",k]];  

}

答案 1 :(得分:1)

如果你想从文本字段转换,那么它应该是

NSString *str = textField.text;

答案 2 :(得分:1)

用以下功能替换您的功能。 比它能正常工作。

- (IBAction)转换{

NSString *str = display.text;

float n = [str floatValue];


  k = (n - 32)*(5/9);



[display setText:[NSString stringWithFormat:@"%f",k]];  

}

答案 3 :(得分:1)

如果您想转换来自farhenite文本字段的值,那么它应该是

-(IBAction) convert  {

    NSString *str = farhenite.text;

    float n = [str floatValue];


      k = (n - 32)*(5/9);



    [display setText:[NSString stringWithFormat:@"%f",k]];  

}

答案 4 :(得分:0)

NSString *str = display.text;

只需替换str声明。