熊猫用搜索字符串更新列

Question

您好，我正在与熊猫一起练习，我试图弄清楚只要有“ Fee”上的匹配项，如何将类别字段设置为Fees。我尝试了一种无效的遮罩技术。谢谢

df = g1_2019[g1_2019['Description'].str.contains('Fee')]
df.head()

Index   Date    No. Description Category
495 3/18/2019   0   Withdrawal RW-ISA:Fee: International Service Fee    Not Categorized
496 3/18/2019   0   International Service Fee Assessed = $0.07 on ...   Not Categorized
650 4/17/2019   0   Withdrawal RW-ISA:Fee: International Service Fee    Not Categorized
651 4/17/2019   0   International Service Fee Assessed = $0.07 on ...   Not Categorized
879 5/17/2019   0   Withdrawal RW-ISA:Fee: International Service Fee    Not Categorized

Answer 1

尝试：

mask = g1_2019['Description'].str.contains('Fee')
g1_2019.loc[mask, "Category"] = "Fees"

Answer 2

您可以考虑使用np.where

import numpy as np
df["Description"] = np.where(df["Description"].str.contains("Fee"),
                             "Fees",
                             df["Description"])