Question

我有两张关注的表 - “videoComments”，“storyComments”。

我需要找到videoComments和storyComments中条目最多的'posterID'。这是我到目前为止的代码，但它只调用videoComments：

$sql = "SELECT (SELECT posterID 
                  FROM videoComments 
              GROUP BY posterID 
              ORDER BY COUNT(posterID) DESC LIMIT 1) ) AS mostSocialUser ";

如何提取它并比较两个表中的posterID COUNT？

Answer 1

试试这个：

SELECT (
    SELECT posterID FROM (
        SELECT posterID FROM videoComments 
        UNION 
        SELECT posterID FROM storyComments
    ) GROUP BY posterID 
      ORDER BY COUNT(posterID) DESC LIMIT 1
) AS mostSocialUser

Answer 2

使用：

   SELECT x.posterid,
          COUNT(y.posterid) + COUNT(z.posterid) AS numComments
     FROM (SELECT vc.posterid
             FROM VIDEOCOMMENTS vc
           UNION 
           SELECT sc.posterid
             FROM STORYCOMMENTS sc) x
LEFT JOIN VIDEOCOMMENTS y ON y.posterid = x.posterid
LEFT JOIN STORYCOMMENTS z ON z.posterid = x.posterid
 GROUP BY x.posterid
 ORDER BY numComments DESC
    LIMIT 1

MySQL - “多数社交用户”，多个表中的评论最多

2 个答案: