Question

我有以下代码：当我尝试从邮递员那里说：

“消息”：“ account.save不是函数”

const account = await Account.find({ "buildings.gateways.devices.verificationCode": code })
    var accountId = account ? account.map(item => item._id) : null

const buildings = _.flatMap(account, a => a.buildings)
const gateways = _.flatMap(buildings, b => b.gateways);
const devices = _.flatMap(gateways, g => g.devices);

// finding deviceId to insert for user from that account
const device = _.filter(devices, d => d.verificationCode === code);

device.patientFirstName = req.body.firstName;
device.patientLastName = req.body.lastName;
account.save();

如果我尝试更改为findOne（），则会显示

“ account.map不是函数”

帐户总是返回值，然后为什么我无法理解它为什么不能映射。

感谢您的帮助。谢谢

Answer 1

.find()返回一个数组，因此您可以运行Array.map()，但需要分别.save()每个文档：

const accounts = await Account.find({ "buildings.gateways.devices.verificationCode": code })
var accountId = account ? account.map(item => item._id) : null

for(let account of accounts){
    await account.save();
}

.findOne()（等待）返回单个文档，因此您不能使用.map()：

const account = await Account.findOne({ "buildings.gateways.devices.verificationCode": code })
var accountId = account ? account._id : null

account.save();

更新文档时，.save不是函数，.map不是函数

1 个答案: