即将到来的代码片段将从用户JSON对象中删除password属性,并将其作为响应返回。发生的是密码属性仍在返回!
const signin = (req, res, next) => {
let requestBody = req.body;
userModel.findUserByEmail(requestBody.email).then(user => {
bcrypt.compare(requestBody.password, user.password, (error, result) => {
if (!result) {
return res.status(500).json({
status: false,
message: 'Auth Failed!',
error
});
}
if (error) {
return res.status(500).json({
error
});
}
let token = jwt.sign({
email: user.email,
userId: user._id
},
process.env.JWT_KEY,
{
expiresIn: "2h"
});
// remonve password key
delete user.password
res.status(200).json({
status: true,
message: 'Authenticated!',
data: {
token,
user
}
});
});
}).catch(error => {
return res.status(500).json({
status: false,
message: 'Auth Failed!',
error
});
});
}
不确定问题是否与异步编译有关
答案 0 :(得分:1)
您可以创建一个没有密码的新对象,并在响应中使用它:
const { password, ...restOfUser } = user
res.status(200).json({
status: true,
message: 'Authenticated!',
data: {
token
user: restOfUser
}
})