我对svg + QT概念还比较陌生。 我创建了一个具有2个状态的svg图标。 我想将此svg图标添加到QPushButton。单击该按钮时，图标应该被切换（显示其他状态）。
有人可以请问我如何在QT中做到这一点吗？用C ++进行QT！
编辑：
我无法上传svg图像，因此无法粘贴svg图像的内容。希望对您有所帮助。
<svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 16 16" height="16" width="16"><g class="nc-icon-wrapper js-transition-icon" data-effect="scale" data-event="click"><g class="js-transition-icon__state" stroke-width="1" fill="#111111" stroke="#111111"><title>archive 2 2</title><g><path data-color="color-2" fill="none" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" d="M2.5.5h11"></path><path data-color="color-2" fill="none" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" d="M11.5 6.5v2h-7v-2"></path><path fill="none" stroke="#111111" stroke-linecap="round" stroke-linejoin="round" stroke-miterlimit="10" d="M.5 3.5h15v11H.5z"></path></g></g><g class="js-transition-icon__state" fill="#111111" aria-hidden="true" style="display: none;"><title>archive 2</title><path data-color="color-2" d="M3,2h10c0.6,0,1-0.4,1-1s-0.4-1-1-1H3C2.4,0,2,0.4,2,1S2.4,2,3,2z"></path> <path fill="#111111" d="M15,4H1C0.4,4,0,4.4,0,5v10c0,0.6,0.4,1,1,1h14c0.6,0,1-0.4,1-1V5C16,4.4,15.6,4,15,4z M12,11H4V7h2v2h4V7h2 V11z"></path></g></g><script>!function(){"use strict";if(!window.requestAnimationFrame){var a=null;window.requestAnimationFrame=function(t,i){var e=(new Date).getTime();a||(a=e);var s=Math.max(0,16-(e-a)),n=window.setTimeout(function(){t(e+s)},s);return a=e+s,n}}function r(t,i,e,s){return 1>(t/=s/2)?e/2*t*t*t*t+i:-e/2*((t-=2)*t*t*t-2)+i}function e(t){return t?[1,0]:[0,1]}function t(t){this.element=t,this.svg=function t(i){var e=i.parentNode;if("svg"!==e.tagName)e=t(e);return e;}(this.element),this.getSize(),this.states=this.element.querySelectorAll(".js-transition-icon__state"),this.time={start:null,total:200},this.status={interacted:!1,animating:!1},this.animation={effect:this.element.getAttribute("data-effect"),event:this.element.getAttribute("data-event")},this.init()}t.prototype.getSize=function(){var t=this.svg.getAttribute("viewBox");this.size=t?{width:t.split(" ")[2],height:t.split(" ")[3]}:this.svg.getBoundingClientRect()},t.prototype.init=function(){var t=this;this.svg.addEventListener(t.animation.event,function(){t.status.animating||(t.status.animating=!0,window.requestAnimationFrame(t.triggerAnimation.bind(t)))})},t.prototype.triggerAnimation=function(t){var i=this.getProgress(t);this.animateIcon(i),this.checkProgress(i)},t.prototype.getProgress=function(t){return this.time.start||(this.time.start=t),t-this.time.start},t.prototype.checkProgress=function(t){if(this.time.total>t)window.requestAnimationFrame(this.triggerAnimation.bind(this));else{this.status={interacted:!this.status.interacted,animating:!1},this.time.start=null;var i=e(this.status.interacted);this.states[i[0]].removeAttribute("aria-hidden"),this.states[i[1]].setAttribute("aria-hidden","true")}},t.prototype.animateIcon=function(t){if(t>this.time.total){t=this.time.total;}if(0>t){t=0;};var i=e(this.status.interacted);this.states[i[0]].style.display=t>this.time.total/2?"none":"block",this.states[i[1]].style.display=t>this.time.total/2?"block":"none","scale"==this.animation.effect?this.scaleIcon(t,i[0],i[1]):this.rotateIcon(t,i[0],i[1])},t.prototype.scaleIcon=function(t,i,e){var s=r(Math.min(t,this.time.total/2),1,-.2,this.time.total/2).toFixed(2),n=r(Math.max(t-this.time.total/2,0),.2,-.2,this.time.total/2).toFixed(2);this.states[i].setAttribute("transform","translate("+this.size.width*(1-s)/2+" "+this.size.height*(1-s)/2+") scale("+s+")"),this.states[e].setAttribute("transform","translate("+this.size.width*n/2+" "+this.size.height*n/2+") scale("+(1-n)+")")},t.prototype.rotateIcon=function(t,i,e){var s=r(t,0,180,this.time.total).toFixed(2);this.states[i].setAttribute("transform","rotate(-"+s+" "+this.size.width/2+" "+this.size.height/2+")"),this.states[e].setAttribute("transform","rotate("+(180-s)+" "+this.size.width/2+" "+this.size.height/2+")")};var i=document.querySelectorAll(".js-transition-icon");if(i)for(var s=0;i.length>s;s++)new t(i[s])}();</script></svg>