Question

我正在node.js（express）和前端之间初始化socket.io。基本上，从nodejs，我正在向私有频道广播。然后，我也想在同一频道上收到此广播的回叫。

这是server.js中的设置：

const port = process.env.PORT || 3000;
var express = require('express');
var app = express();
var http = require('http').Server(app);
var io = require('socket.io')(http);


const api = require('../api/AuthController')


var server = http.listen(3000, () => {
  console.log('server is running on port', server.address().port);
});

const routes = require('../api/routes');
routes(app,io);

//socket config
global.io = io; //added

然后在AuthController中，我正在使用global.io进行发射，并在私有通道中进行接收：

global.io.emit(`news${user._id}`, { hello: 'new request');
                        global.io.on('conection', function (socket) {
                            socket.on(`news${user._id}`, function (message) {
                                console.log('from console', message.value);
                            });
                        });

我可以很好地向前端发射信号，但是当前端在同一通道上发射回来时，我什么也收不到。

感谢您的帮助。

谢谢

修改

前端代码：

import 'dart:async';
import 'package:flutter/material.dart';
import 'package:flutter/services.dart';
import 'package:adhara_socket_io/adhara_socket_io.dart';
import 'package:geocoder/geocoder.dart';

const String URI = "http://10.0.2.2:3000/";

class MyHomePage extends StatefulWidget {
  MyHomePage({Key key, this.title}) : super(key: key);
  final String title;

  @override
  _MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {
  _MyHomePageState();

  List<String> toPrint = ["trying to connect"];
  SocketIOManager manager;
  Map<String, SocketIO> sockets = {};
  Map<String, bool> _isProbablyConnected = {};
  bool newtripRequest = false;
  var pickupController;
  var dropoffController;
  SocketIO socketController;
  var driver = 'driver';
  String socketIdentifier;

  @override
  void initState() {
    super.initState();
    manager = SocketIOManager();
    initSocket("default");

  }

  @override
  void dispose() {
    super.dispose();
  }




  initSocket(String identifier) async {
    setState(() => _isProbablyConnected[identifier] = true);
    SocketIO socket = await manager.createInstance(SocketOptions(
        //Socket IO server URI
        URI,
        nameSpace: (identifier == "namespaced") ? "/adhara" : "/",
        //Query params - can be used for authentication
        query: {
          "auth": "--SOME AUTH STRING---",
          "info": "new connection from adhara-socketio",
          "timestamp": DateTime.now().toString()
        },
        //Enable or disable platform channel logging
        enableLogging: false,
        transports: [
          Transports.WEB_SOCKET /*, Transports.POLLING*/
        ] //Enable required transport
        ));
    setState(() {
      socketIdentifier = identifier;
    });
    socket.onConnect((data) {
      pprint("connected...");
      pprint(data);
      sendMessage('news', 'yes', socketIdentifier);
    });

    socket.onConnectError(pprint);
    socket.onConnectTimeout(pprint);
    socket.onError(pprint);
    socket.onDisconnect(pprint);
    socket.on("news", (data) => newTripRquest(data));
    socket.connect();
    sockets[identifier] = socket;
  }

  bool isProbablyConnected(String identifier) {
    return _isProbablyConnected[identifier] ?? false;
  }

  disconnect(String identifier) async {
    await manager.clearInstance(sockets[identifier]);
    setState(() => _isProbablyConnected[identifier] = false);
  }

  sendMessage(privateChannel, messageBody, identifier) {
    //pprint("sending message from '$identifier'...");
    sockets[identifier].emit(driverChannel, [
      {'response' : messageBody}]);
    //pprint("Message emitted from '$identifier'...");
  }

  pprint(data) {
    setState(() {
      if (data is Map) {
        data = json.encode(data);
      }
      print(data);
      toPrint.add(data);
    });
  }

Answer 1

您遇到了拼写错误（“对接”），并且emit对象中没有右括号。

这是AuthController代码的固定版本：

global.io.emit(`news${user._id}`, { hello: 'new request' });

global.io.on('connection', function (socket) {
  socket.on(`news${user._id}`, function (message) {
    console.log('from console', message.value);
  });
});

希望对您有帮助！

node.js无法在socket.io的专用通道上接收

1 个答案: