Question

我正在努力消除我的SQL技能，并需要一些帮助以下查询。我目前使用的数据库是mysql。

我想要检索分配给'tag2'和'tag4'的所有FlashCard。根据现有表的内容（如下面的摘录所示），查询应返回两行：FlashCard_ID 1和2.

我如何制定此查询？已经有一段时间了，因为我不得不做这样的事情。

mysql> select * from flashcard;
+--------------+------------+----------+
| FLASHCARD_ID | QUESTION   | ANSWER   |
+--------------+------------+----------+
|            1 | Question 1 | Answer 1 |
|            2 | Question 2 | Answer 2 |
|            3 | Question 3 | Answer 3 |
+--------------+------------+----------+
3 rows in set (0.00 sec)

mysql> select * from tag;
+--------+------+
| TAG_ID | NAME |
+--------+------+
|      1 | tag1 |
|      2 | tag2 |
|      3 | tag3 |
|      4 | tag4 |
|      5 | tag5 |
+--------+------+
5 rows in set (0.00 sec)

mysql> select * from flashcard_tags;
+--------+--------------+
| TAG_ID | FLASHCARD_ID |
+--------+--------------+
|      2 |            1 |
|      3 |            1 |
|      4 |            1 |
|      2 |            2 |
|      4 |            2 |
|      5 |            2 |
+--------+--------------+
6 rows in set (0.00 sec)

Answer 1

SELECT  f.*
FROM    (
        SELECT  flashcard_id
        FROM    tags t
        JOIN    flashcard_tags ft
        ON      ft.tag_id = t.tag_id
        WHERE   t.name IN ('tag2', 'tag4')
        GROUP BY
                flashcard_id
        HAVING  COUNT(*) = 2
        ) ft
JOIN    flashcard f
ON      f.flashcard_id = ft.flashcard_id

Answer 2

SELECT f.*
FROM flashcard f
  INNER JOIN flashcard_tags ft1 ON f.FLASHCARD_ID = ft1.FLASHCARD_ID
  INNER JOIN tag t1 ON ft1.TAG_ID = t1.TAG_ID AND t1.NAME = 'tag2'
  INNER JOIN flashcard_tags ft2 ON f.FLASHCARD_ID = ft2.FLASHCARD_ID
  INNER JOIN tag t2 ON ft2.TAG_ID = t2.TAG_ID AND t2.NAME = 'tag4'

Answer 3

这是另一个有效的查询。这个不使用子查询，是我最终在我的Hibernate代码中使用的。

select  fc.FLASHCARD_ID, 
        fc.QUESTION, 
        fc.ANSWER
from    FLASHCARD fc
            inner join FLASHCARD_TAGS fc_t
                on fc.FLASHCARD_ID=fc_t.FLASHCARD_ID 
            inner join TAG t 
                on fc_t.TAG_ID=t.TAG_ID
where   t.Name in ('tag2', 'tag4')
group by fc.FLASHCARD_ID 
having count(t.TAG_ID)=2

帮助查询关系表

3 个答案: