ORDER BY日期，但保留GROUP BY分组

Question

我按ClientID和位置将查询分组如下：

SELECT
    lph.ClientID
    ,lph.LocationID
    ,MAX(c.ClientName) AS ClientName
    ,MAX(cp.ClientName) AS ClientPartnerName
    ,MAX(c.BillingContactName) AS BillingContactName
    ,MAX(c.BillingEmail) AS BillingEmail
FROM [billing].[TEST_LicensePackageHeader] lph
    LEFT JOIN [app].[TEST_Client] c
        ON lph.ClientID = c.ClientID
    LEFT JOIN [billing].[TEST_LicensePackageClientPartner] lpcp
        ON lph.PackageID = lpcp.PackageID
    LEFT JOIN [app].[TEST_Client] cp --client partner
        ON lpcp.ClientPartnerID = cp.ClientID
WHERE lph.LicenseExpirationDate BETWEEN @FilterStartDate AND @FilterEndDate
    AND ( ((LEN(@ClientPartnerSearchString) > 0) AND (cp.ClientName LIKE '%' + @ClientPartnerSearchString + '%') )
    OR ((LEN(@ClientPartnerSearchString) = 0)) )
GROUP BY lph.ClientID, lph.LocationID
ORDER BY lph.ClientID, lph.LocationID, MAX(lph.LicenseExpirationDate)

我想对MAX（LicenseExpirationDate）DESC进行排序，以便按ClientID分组以MAX（LicenseExpirationDate）DESC的顺序显示。

仅查看这3列，我需要将其分组如下：

| ClientID | LocationID | MAX(LicenseExpirationDate) |
----------------------------------------------------
| 4        | 3          | 01/03/2019                 |
| 4        | 7          | 01/17/2020                 |
| 1        | 1          | 02/04/2018                 |
| 1        | 3          | 07/13/2018                 |
| 2        | 8          | 09/22/2015                 |
| 2        | 3          | 01/30/2017                 |

基本上，我只需要MAX（LicenseExpirationDate）以排序顺序为先，同时将ClientID和LocationID的分组保持在一起。

希望这是有道理的。我不确定如何在SQL Server中执行此操作。谢谢！

Answer 1

我想你想要

order by max(max(LicenseExpirationDate)) over (partition by clientId) desc,
         clientId,
         max(LicenseExpirationDate) asc

这将在整个客户端中按最大LicenseExpirationDate的顺序对客户端进行排序。然后，它在每个客户端中按LicenseExpirationDate对每一行进行排序。