Question

试图构造一个正则表达式，以查找任何字符模式，后跟双引号

此正则表达式可以正确定位每次出现的情况

(\S"")

给出以下示例

$string='"WEINSTEIN","ANTONIA \"TOBY"","STILES","HOOPER \"PETER"","HENDERSON",';
$pattern = '(\S"")';
$replacement = '\\""';
$result=preg_replace($pattern, $replacement, $string);

我的结果竟然是

"WEINSTEIN","ANTONIA \"TOB\"","STILES","HOOPER \"PETE\"","HENDERSON"

但是我正在寻找

"WEINSTEIN","ANTONIA \"TOBY\"","STILES","HOOPER \"PETER\"","HENDERSON"

我知道替换项是删除/替换整个匹配项，但是如何删除除第一个字母之外的所有字母，而不是完全替换呢？

Answer 1

您可以将模式更改为使用正向后视，以免捕获非空格字符：

$string='"WEINSTEIN","ANTONIA \"TOBY"","STILES","HOOPER \"PETER"","HENDERSON",';
$pattern = '/(?<=\S)""/';
$replacement = '\\""';
$result=preg_replace($pattern, $replacement, $string);
echo $result;

输出

"WEINSTEIN","ANTONIA \"TOBY\"","STILES","HOOPER \"PETER\"","HENDERSON",

Demo on 3v4l.org

PHP REGEX查找和替换模式

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