Question

我正在使用自定义验证器函数，该函数使用RegEx来确定匹配项。

newPassword: [
          null,
          Validators.compose([
            Validators.required,
            // check whether the entered password has a number
            CustomValidators.patternValidator(/\d/, {
              hasNumber: true
            }),
            // check whether the entered password has upper case letter
            CustomValidators.patternValidator(/[A-Z]/, {
              hasCapitalCase: true
            }),
            // check whether the entered password has a lower case letter
            CustomValidators.patternValidator(/[a-z]/, {
              hasSmallCase: true
            }),
            // check whether the entered password has a special character
            CustomValidators.patternValidator(
              /[ !@#$%^&*()_+\-=\[\]{};':"\\|,.<>\/?]/,
              {
                hasSpecialCharacters: false
              }
            ),
            Validators.minLength(8)
          ])
        ]

函数看起来像这样

export class CustomValidators {
static patternValidator(regex: RegExp, error: ValidationErrors): ValidatorFn {
return (control: AbstractControl): { [key: string]: any } => {
  if (!control.value) {
    // if control is empty return no error
    return null;
  }

  // test the value of the control against the regexp supplied
  const valid = regex.test(control.value);

  // if true, return no error (no error), else return error passed in the second parameter
  return valid ? null : error;
};
}

我的问题是我该如何增强它，例如要求2个大写字母，因为我的功能仅检查是否存在大写字母。

Answer 1

您需要在正则表达式中添加一个量词。量词{2,}表示它必须至少匹配两次

CustomValidators.patternValidator(/[A-Z]{2,}/, {
              hasCapitalCase: true
 }),

如何验证密码以包含多个大写字母

1 个答案: