Question

问题是关于在xml文件/中定义的骆驼路线中使用由mapstruct生成的Spring bean 我有以下配置：春季java

### use for loop
myfun_stupid1 <- function(x){

  ncols = dim(x)[2]

  likelihood <- function(mu){
    # I have to difine my function with the shape of input data!
    # If I have a dataframe with 100 columnss, my hands will be broken...
    # Can we do it automatically? 
    value = 0
    for (col_num in 1:ncols)
      value = value + sum((x[,col_num] - mu[col_num])^2) 
    return(value)
  }
  return(optim(par = rep(0,ncols),fn = likelihood,method = 'L-BFGS-B',
               lower = rep(-20,ncols), upper = rep(20,ncols))$par)
}  
myfun_stupid1(input_data_c2)


### use vectorlization 
myfun_stupid2 <- function(x){

  ncols = dim(x)[2]
  x <- as.matrix(x)

  likelihood <- function(mu){
    # I have to difine my function with the shape of input data!
    # If I have a dataframe with 100 columnss, my hands will be broken...
    # Can we do it automatically? 
    x_minus = sweep(x, MARGIN = 2, mu)
    # see sweep(x = matrix(1:12,6,2),MARGIN = 2,c(1,2)), matrix minus a vector
    value <- sum(diag(t(x_minus) %*%  x_minus))
    return(value)
  }

  return(optim(par = rep(0,ncols),fn = likelihood,method = 'L-BFGS-B',
               lower = rep(-20,ncols), upper = rep(20,ncols))$par)
}
myfun_stupid2(input_data_c2)

@Component
public class OrderMapperImpl implements OrderMapper {

    @Override
    public CreateOrderRequest map(Order value) {
    }
}

骆驼xml路线

@Bean
public Jaxb2Marshaller jaxbUnmarshaller() {
    Jaxb2Marshaller marshaller = new Jaxb2Marshaller();
    marshaller.setPackagesToScan("ru.sth.package");
    return marshaller;
    }

例外是

<?xml version="1.0" encoding="UTF-8"?>
<routes>
...
    <route id="from_somewhere">
        <from uri="{{random.endpoint}}"/>
        <log message="Received message from ${body}"/>
        <to uri="bean:jaxbUnmarshaller?method=unmarshal"/>
        <to uri="bean:orderMapper?method=map"/>
        <to uri="direct:toSomewhere" pattern="InOut"/>
    </route>
...
</routes>

有趣的事情是，解组器一切正常。映射器也是由mapstruct生成的，并在编译时生成有任何想法吗？

Answer 1

Spring组件扫描将创建的bean是OrderMapperImpl。在Spring中，默认情况下，带注释的Bean的名称是从类的简单名称生成的，首字母为小写。

因此，在您的情况下，bean的名称为orderMapperImpl，您应该在骆驼xml定义中使用它。

如何在xml中定义的骆驼路线中使用Spring bean

1 个答案: