经过5个小时的尝试,请耐心等待。筛选了与此相关的所有stackoverflow问题,但找不到答案。
该代码是gmail解析器-适用于大多数电子邮件,但某些电子邮件会导致UnicodeDecodeError。问题是“ raw_email.decode('utf-8')”,但是对其进行更改(请参阅主题标签注释)会导致下面的另一个问题。
谢谢!
# Source: https://stackoverflow.com/questions/7314942/python-imaplib-to-get-gmail-inbox-subjects-titles-and-sender-name
import datetime
import time
import email
import imaplib
import mailbox
from vars import *
import re # to remove links from str
import string
EMAIL_ACCOUNT = 'gmail_login'
PASSWORD = 'gmail_psswd'
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login(EMAIL_ACCOUNT, PASSWORD)
mail.list()
mail.select('inbox')
result, data = mail.uid('search', None, "ALL") # (ALL/UNSEEN)
id_list = data[0].split()
email_rev = reversed(id_list) # Returns a type list.reverseiterator, which is not list
email_list = list(email_rev)
i = len(email_list)
todays_date = time.strftime("%m/%d/%Y")
for x in range(i):
latest_email_uid = email_list[x]
result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
raw_email = email_data[0][1] # Returns a byte
raw_email_str = raw_email.decode('utf-8') # Returns a str
#raw_email_str = base64.b64decode(raw_email_str1) # Tried this but didn't work.
#raw_email_str = raw_email.decode('utf-8', errors='ignore') # Tried this but caused a TypeError down where var subject is created because something there is expecting a str or byte-like
email_message = email.message_from_string(raw_email_str)
date_tuple = email.utils.parsedate_tz(email_message['Date'])
date_short = f'{date_tuple[1]}/{date_tuple[2]}/{date_tuple[0]}'
# Header Details
if date_short == '12/23/2019':
#if date_tuple:
# local_date = datetime.datetime.fromtimestamp(email.utils.mktime_tz(date_tuple))
# local_message_date = "%s" %(str(local_date.strftime("%a, %d %b %Y %H:%M:%S")))
email_from = str(email.header.make_header(email.header.decode_header(email_message['From'])))
subject = str(email.header.make_header(email.header.decode_header(email_message['Subject'])))
#print(subject)
if email_from.find('restaurants@uber.com') != -1:
print('yay')
# Body details
if email_from.find('restaurants@uber.com') != -1 and subject.find('Payment Summary') != -1:
for part in email_message.walk():
if part.get_content_type() == "text/plain":
body = part.get_payload(decode=True)
body = body.decode("utf-8") # Convert byte to str
body = body.replace("\r\n", " ")
text = re.sub(r'\w+:\/{2}[\d\w-]+(\.[\d\w-]+)*(?:(?:\/[^\s/]*))*', '', body) # removes url links
text2 = text.translate(str.maketrans('', '', string.punctuation))
body_list = re.sub("[^\w]", " ", text2).split()
print(body_list)
print(date_short)
else:
continue
答案 0 :(得分:1)
这里是一个示例,说明如何使用python标准库中的imapclient
和email.*
模块检索和读取邮件部分:
from imapclient import IMAPClient
import email
from email import policy
def walk_parts(part, level=0):
print(' ' * 4 * level + part.get_content_type())
# do something with part content (applies encoding by default)
# part.get_content()
if part.is_multipart():
for part in part.get_payload():
get_parts(part, level + 1)
# context manager ensures the session is cleaned up
with IMAPClient(host="your_mail_host") as client:
client.login('user', 'password')
# select some folder
client.select_folder('INBOX')
# do something with folder, e.g. search & grab unseen mails
messages = client.search('UNSEEN')
for uid, message_data in client.fetch(messages, 'RFC822').items():
email_message = email.message_from_bytes(
message_data[b'RFC822'], policy=policy.default)
print(uid, email_message.get('From'), email_message.get('Subject'))
# alternatively search for specific mails
msgs = client.search(['SUBJECT', 'some subject'])
#
# do something with a specific mail:
#
# fetch a single mail with UID 12345
raw_mails = client.fetch([12345], 'RFC822')
# parse the mail (very expensive for big mails with attachments!)
mail = email.message_from_bytes(
raw_mails[12345][b'RFC822'], policy=policy.default)
# Now you have a python object representation of the mail and can dig
# into it. Since a mail can be composed of several subparts we have
# to walk the subparts.
# walk all parts at once
for part in mail.walk():
# do something with that part
print(part.get_content_type())
# or recurse yourself into sub parts until you find the interesting part
walk_parts(mail)
请参阅email.message.EmailMessage的文档。在那里,您找到了所有需要读入邮件中的信息。
答案 1 :(得分:0)
使用“ISO 8859-1”代替“utf-8”
答案 2 :(得分:0)
我遇到了同样的问题 经过大量研究后,我意识到我只需要使用 message_from_bytes
中的 email
函数而不是使用 message_from_string
因此对于您的代码只需替换:
raw_email_str = raw_email.decode('utf-8')
email_message = email.message_from_string(raw_email_str)
到
email_message = email.message_from_bytes(raw_email)
应该像魅力一样工作:)