Question

我有笨拙的方法，包含多个丑陋的条件语句。例如：

public String getKafkaTopicName(EvntMsg evntMsg) {
    Table table = fillerTableSection(evntMsg);
    String[] msgDetails = table.getMessageString().split("\\^");
    String topicName;
    if (("QUEUE_R".equals(table.getDeliveryChannel()) && "A".equals(msgDetails[0])) ||
            ("M".equals(table.getDeliveryChannel()) && "F".equals(msgDetails[0])) ||
            ("QUEUE_Q".equals(table.getDeliveryChannel()) && "S".equals(msgDetails[0])) ||
            ("QUEUE_W".equals(table.getDeliveryChannel()) && "S".equals(msgDetails[0])) ||
            ("QUEUE_Q".equals(table.getDeliveryChannel()) && "C".equals(msgDetails[0]) && "DD_SRC_MESS".equals(table.getCode())) ||
            ("QUEUE_Q".equals(table.getDeliveryChannel()) && "C".equals(msgDetails[0]) && "DD_TGT_MESS".equals(table.getCode()))) {
        topicName = paramsHelper.getKafkaTopicNameBalance();
    } else if (("SMS3DS_CHECK".equals(table.getDeliveryChannel())) ||
            ("SMS3DS".equals(table.getDeliveryChannel()))) {
        topicName = paramsHelper.getKafkaTopicNameOtp();
    } else if (("SBRF_I".equals(table.getDeliveryChannel()) && "I".equals(msgDetails[0])) ||
            ("SBRF_B".equals(table.getDeliveryChannel()) && "B".equals(msgDetails[0])) ) {
        topicName = paramsHelper.getKafkaTopicNameIssuing();
    } else if (("QUEUE_Q".equals(table.getDeliveryChannel()) && "C".equals(msgDetails[0]) && "C0".equals(table.getCode().substring(0, 2))) ||
            ("QUEUE_R".equals(table.getDeliveryChannel()) && "AP".equals(msgDetails[0])) ||
            ("QUEUE_D".equals(table.getDeliveryChannel()) && "AP".equals(msgDetails[0]))) {
        topicName = paramsHelper.getKafkaTopicNameNotify();
    } else {
        topicName = paramsHelper.getKafkaTopicNameUndefined();
    }
    return topicName;
}

如何对其进行修改以提高可读性？

Answer 1

您可以做的是隔离返回布尔值的方法

boolean test0(Table table, String[] msgDetails){
   return "QUEUE_R".equals(table.getDeliveryChannel()) && "A".equals(msgDetails[0])) ||
            ("M".equals(table.getDeliveryChannel()) && "F".equals(msgDetails[0])) ||
            ("QUEUE_Q".equals(table.getDeliveryChannel()) && "S".equals(msgDetails[0])) ||
            ("QUEUE_W".equals(table.getDeliveryChannel()) && "S".equals(msgDetails[0])) ||
            ("QUEUE_Q".equals(table.getDeliveryChannel()) && "C".equals(msgDetails[0]) && "DD_SRC_MESS".equals(table.getCode())) ||
            ("QUEUE_Q".equals(table.getDeliveryChannel()) && "C".equals(msgDetails[0]) && "DD_TGT_MESS".equals(table.getCode()))
}

带有丑陋条件语句的重构方法

1 个答案: