我要转换以下
Future<UserDetl> f = AppDatabase().userById('55e62a90-273c-11ea-9441-f75d5cd0114b');
进入List<UserDetl> lstUser
class UserDetl {
String userId;
String userName;
String userPlace;
String userUrl;
UserDetl(this.userId,this.userName, this.userPlace, this.userUrl);
}
我想从列表中获取用户名
String user = lstUser[0].userName;
答案 0 :(得分:0)
尝试一下!
getUser() async {
UserDetl tmp = await AppDatabase().userById('55e62a90-273c-11ea-9441-f75d5cd0114b');
if(tmp!=null)
setState((){
UserDetl u = v;
});
}
答案 1 :(得分:0)
您只需要用结果构建一个列表:
Future<UserDetl> f = AppDatabase().userById('55e62a90-273c-11ea-9441-f75d5cd0114b');
UserDetl user = await f;
List<UserDetl> lstUser = [user];
答案 2 :(得分:0)
Future<UserDetl> f = //get your Futuredata
UserDetl user = await f;
List<UserDetl> lstUser = [user];//add in list
//you also can get it from list like:
UserDetl user = lstUser[0];