Question

在Jenkins中完成上传（每个进度的底部栏状态）。但是看不到从詹金斯定位或获取上传文件的选项。

这是带有File参数的简单脚本，

properties(
    [
        parameters(
            [ file(name: "file1.zip", description: 'Choose path to upload file1.zip from local system.'),
              file(name: "file2.zip", description: 'Choose path to upload file2.zip from local system.') ]
            )
    ]
)

node {
    stage("Fetch Uploaded File") {
        sh '''
        ls -l file1.zip file2.zip
        ls -l ${WORKSPACE}/file1.zip ${WORKSPACE}/file2.zip
        '''
     }


}

每隔一个帖子都尝试了def输入文件选项，但是没有运气可以上传文件。有输入吗？

    def inputFile = input message: 'Upload file', parameters: [file(name: 'data.ear')]
    new hudson.FilePath(new File("$workspace/data.ear")).copyFrom(inputFile)
    inputFile.delete()

在上面粘贴了脚本化的完整管道，得到以下错误。

[Pipeline] {
[Pipeline] stage
[Pipeline] { (Fetch Uploaded File)
[Pipeline] sh
[testSh] Running shell script
+ ls -l file1.zip file2.zip
ls: cannot access file1.zip: No such file or directory
ls: cannot access file2.zip: No such file or directory
[Pipeline] }
[Pipeline] // stage
[Pipeline] }
[Pipeline] // node
[Pipeline] End of Pipeline
ERROR: script returned exit code 2
Finished: FAILURE

Answer 1

这是一个已知的错误JENKINS-27413。

但是，有一个具有解决方法的库可以为您https://github.com/janvrany/jenkinsci-unstashParam-library提供帮助。如自述文件所述，您可以将此库添加到Jenkins（Extending with Shared Libraries）中，并按以下方式使用它：

library "jenkinsci-unstashParam-library"
node {
   def file_in_workspace = unstashParam "file"
   sh "cat ${file_in_workspace}"
}

在Jenkins中获取上传的文件

1 个答案: