Question

因此，我有两个带有名称的数组，我想检查一下，给定两个名称，它们是否分别位于一个数组中且处于相同位置。例如，如果我具有名称“ Mike”和“ Charles”以及数组[“ John”，“ Mike”，“ Sophie”]和[“ Ellie”，“ Charles”，“ Ryan”]，则返回true。

我正在制作一个“秘密圣诞老人”程序，我不希望夫妻彼此像“秘密圣诞老人”一样。

Answer 1

Array.IndexOf听起来像您要找的东西。

string[] firstArray = new string[] { "John", "Mike", "Sophie" };
string[] secondArray = new string[] { "Ellie", "Charles", "Ryan" };

string firstName = "Mike";
string secondName = "Charles";

if (!firstArray.Contains(firstName) || !secondArray.Contains(secondName))
    return false;

return Array.IndexOf(firstArray, firstName) == Array.IndexOf(secondArray, secondName);

Answer 2

    string[] firstArray = new string[] { "John", "Mike", "Sophie" };
    string[] secondArray = new string[] { "Ellie", "Charles", "Ryan" };

    string firstName = "Sophie";
    string secondName = "Ryan";     
    return (Array.IndexOf(firstArray, firstName) == Array.IndexOf(secondArray, 
           secondName));

Answer 3

您可以尝试这个。

var firstArray = new string[] { "John", "Mike", "Sophie" };
var secondArray = new string[] { "Ellie", "Charles", "Ryan" };

var firstName = "Mike";
var secondName = "Charles";

var firstNameIndex = firstArray.ToList().FindIndex(a => a == firstName);
var secondNameIndex = secondArray.ToList().FindIndex(a => a == secondName);

if (firstNameIndex == secondNameIndex && (firstNameIndex != -1 || secondNameIndex != -1))
{
return  true;
}
 else
{
return  false;
}

Answer 4

您可以尝试以下操作

        var index1 = Array.IndexOf(new[] { "John", "Mike", "Sophie" }, "Mike");
        var index2 = Array.IndexOf(new[] { "Ellie", "Charles", "Ryan" } , "Charles");
        return index1 == index2 && index1 != -1;

检查两个字符串是否位于两个不同的数组中但位置相同

4 个答案: