Question

我有以下对象数组

  let attendanceGroup =  [
    0: {-Lwk9gsgfsQHkUljyyr: "absent"}
    1: {-Lwk98aagfaFTu0qNFJD: "absent"}
    2: {-Lwk9BgBg05SygiRPKw8: "absent"}
    3: {-LwkasdfgHHCHw9e-3vq: "absent"}
    ]

let membersPresent = [
0: {uid: -Lwk9BgBg05SygiRPKw8}
1: {uid: LwkasdfgHHCHw9e-3vq}
]

我需要找到例如-Lwk98aagfaFTu0qNFJD的密钥，然后我需要更改“不存在”以显示。

我尝试只进行一次foreach，然后输入uid（即每个密钥中的键）。在这里，我循环其他一些datamemberPresent，然后取出一个匹配的uid，我需要将其更改为present。

membersPresent.forEach(present => {
  attendanceGroup[present.uid] = 'present';
})

这不起作用。有什么想法可以帮助我找到钥匙，然后将价值从现在改变为缺失？

Answer 1

尝试使用array.map

直接搜索

const searchKey = '-Lwk98aagfaFTu0qNFJD';
const data = [
    {'-Lwk9gsgfsQHkUljyyr': "absent"},
    {'-Lwk98aagfaFTu0qNFJD': "absent"},
    {'-Lwk9BgBg05SygiRPKw8': "absent"},
    {'-LwkasdfgHHCHw9e-3vq': "absent"}
];  
data.map(item => {
    item[searchKey]? item[searchKey] = 'present': ''
})
console.log(data);

如果要比较另一个阵列的丢失，请选择此方法。

解析主数组。
检查数组中的每个项目是否在membersPresent数组中存在。
如果存在搜索项，则将其替换。

const membersPresent = [
    {uid: '-Lwk9BgBg05SygiRPKw8'},
    {uid: 'LwkasdfgHHCHw9e-3vq'}
]
const data = [
    {'-Lwk9gsgfsQHkUljyyr': "absent"},
    {'-Lwk98aagfaFTu0qNFJD': "absent"},
    {'-Lwk9BgBg05SygiRPKw8': "absent"},
    {'-LwkasdfgHHCHw9e-3vq': "absent"}
];  
data.map(item => {
    const dataItem = membersPresent.find(eachitem => eachitem.uid === Object.keys(item)[0])
    if(dataItem) {
        item[Object.keys(item)[0]] = 'present';
    }
})
console.log(data);

希望这就是您想要的。

Answer 2

let attendanceGroup = [
    {"-Lwk9gsgfsQHkUljyyr": "absent"},
    {"-Lwk98aagfaFTu0qNFJD": "absent"},
    {"-Lwk9BgBg05SygiRPKw8": "absent"},
    {"-LwkasdfgHHCHw9e-3vq": "absent"}
]

let membersPresent = [
    {uid: "-Lwk98aagfaFTu0qNFJD"},
    {uid: "-LwkasdfgHHCHw9e-3vq"}
]

membersPresent.forEach(present => {
    let uid = present.uid; // User id of member who is present
    // Search the user in attendanceGroup
    for(let idx in attendanceGroup){ // idx is index of element i.e. 0,1,2,3,etc.
        let member = attendanceGroup[idx]; // member from attendanceGroup. Ex {"-Lwk9gsgfsQHkUljyyr": "absent"}
        if(uid in member) // Check if member id is same as given User id
            attendanceGroup[idx][uid] = 'present'; // mark present
    }
})

console.log(attendanceGroup)

输出

[ { '-Lwk9gsgfsQHkUljyyr': 'absent' },
  { '-Lwk98aagfaFTu0qNFJD': 'present' },
  { '-Lwk9BgBg05SygiRPKw8': 'absent' },
  { '-LwkasdfgHHCHw9e-3vq': 'present' } ]

查找密钥，然后替换值

2 个答案: