Question

我有一个从API获得的对象数组。属性名称是动态的（意味着我没有所有这些属性的详尽列表）。如何获得所有不同对象的数组？合同规定，如果键相等，则值也相等。我试着环顾四周，但没有发现完全像这个问题。

[                                                                                                                                                                                           20:31:28
  {
    'product-management': 'Product management'
  },
  {
    'product-development': 'Product development'
  },
  {
    'client-work': 'Client work'
  },
  {
    'client-work': 'Client work'
  },
  {
    'product-development': 'Product development'
  },
  {
    'client-work': 'Client work'
  },
  {
    'product-development': 'Product development'
  }
]

Answer 1

将数组扩展为Object.assign()，将所有对象合并为一个对象。由于所有对象的属性都是唯一的，因此重复项将仅保留一个键（和值）。然后将Object.entries()转换为[key，value]对，并映射回单个对象：

const data = [{"product-management":"Product management"},{"product-development":"Product development"},{"client-work":"Client work"},{"client-work":"Client work"},{"product-development":"Product development"},{"client-work":"Client work"},{"product-development":"Product development"}]

const result = Object.entries(Object.assign({}, ...data))
  .map(([k, v]) => ({ [k]: v }))
  
console.log(result)

使用@Bergi's suggestion，您还可以在删除重复项的同时将其转换为更精巧的API：

const data = [{"product-management":"Product management"},{"product-development":"Product development"},{"client-work":"Client work"},{"client-work":"Client work"},{"product-development":"Product development"},{"client-work":"Client work"},{"product-development":"Product development"}]

const result = Object.entries(Object.assign({}, ...data))
  .map(([key, value]) => ({ key, value }))
  
console.log(result)

从对象数组中删除重复的对象副本

1 个答案: