Question

我有两个数组，需要通过搜索第一个数组中的位置来更新第二个数组。

let arr1 = [{"LEVEL":4,"POSITION":"RGM"},{"LEVEL":5,"POSITION":"GM"},{"LEVEL":5,"POSITION":"GMH"}]

let arr2 = [{"EMAIL":"test1@stc.com","POSITION":"GM"},
            {"EMAIL":"test2@stc.com","POSITION":"GMH"},
            {"EMAIL":"test3@stc.com","POSITION":"RGM"},
            {"EMAIL":"test3@CSR.COM.AU","POSITION":"GM"}]

输出数组

 output  = [ {"LEVEL":5,"EMAIL":"test1@stc.com","POSITION":"GM"}, 
                {"LEVEL":5,"EMAIL":"test2@stc.com",""POSITION":"GMH"}, 
                {"LEVEL":4,"EMAIL":"test3@stc.com","POSITION":"RGM"}, 
                {"LEVEL":5,"EMAIL":"test3@CSR.COM.AU","POSITION":"GM"}]

我尝试使用以下代码进行过滤，但给出了空数组，因此无法继续进行操作：

const output =arr1.filter((item) => {
  return arr2.indexOf(item.POSITION) !== -1 && (item.POSITION)
});

Answer 1

我想您可以使用map创建一个新数组。您可以在此处使用find为当前LEVEL获取正确的POSITION属性。

以下是一个智能解决方案：

const positions = [{"LEVEL":4,"POSITION":"RGM"},{"LEVEL":5,"POSITION":"GM"},{"LEVEL":5,"POSITION":"GMH"}];
const emails = [{"EMAIL":"test1@stc.com","POSITION":"GM"},{"EMAIL":"test2@stc.com","POSITION":"GMH"},{"EMAIL":"test3@stc.com","POSITION":"RGM"},{"EMAIL":"test3@CSR.COM.AU","POSITION":"GM"}];

const result = emails.map(email => {
  email['LEVEL'] = positions.find(p => p['POSITION'] === email['POSITION'])['LEVEL'];
  return email;
})

console.log(result);

摘自Array.prototype.map()文档：

map（）方法创建一个新数组，其结果是在调用数组中的每个元素上调用提供的函数。

摘自Array.prototype.find()文档：

find（）方法返回提供的数组中满足提供的测试功能的第一个元素的值。

我希望这会有所帮助！

Answer 2

面向初学者的另一种解决方案：

let arr1 = [{"LEVEL":4,"POSITION":"RGM"},{"LEVEL":5,"POSITION":"GM"},{"LEVEL":5,"POSITION":"GMH"}]

let arr2 = [{"EMAIL":"test1@stc.com","POSITION":"GM"},
            {"EMAIL":"test2@stc.com","POSITION":"GMH"},
            {"EMAIL":"test3@stc.com","POSITION":"RGM"},
            {"EMAIL":"test3@CSR.COM.AU","POSITION":"GM"}]

function addLevel() {
    const resultingArray = [];
    arr2.forEach(itemarray2 => {
        const copyOfArrayItem2 = Object.assign({}, itemarray2);        
        resultingArray.push(copyOfArrayItem2);
        const itemArray1 = arr1.find(x => x.POSITION === itemarray2.POSITION);
        if(itemArray1) {
            copyOfArrayItem2.LEVEL = itemArray1.LEVEL;
        }
    });
    return resultingArray;
}


const newArray = addLevel();
console.log(newArray);

Answer 3

您可以使用Map并使用LEVEL映射新对象。

var array1 = [{ LEVEL: 4, POSITION: "RGM" }, { LEVEL: 5, POSITION: "GM" }, { LEVEL: 5, POSITION: "GMH" }],
    array2 = [{ EMAIL: "test1@stc.com", POSITION: "GM" }, { EMAIL: "test2@stc.com", POSITION: "GMH" }, { EMAIL: "test3@stc.com", POSITION: "RGM" }, { EMAIL: "test3@CSR.COM.AU", POSITION: "GM" }],
    levels = array1.reduce((m, { LEVEL, POSITION }) => m.set(POSITION, LEVEL), new Map),
    result = array2.map(o => Object.assign({ LEVEL: levels.get(o.POSITION) }, o));

console.log(result);

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Answer 4

最简单的方法是：

let arr1 = [{"LEVEL":4,"POSITION":"RGM"},{"LEVEL":5,"POSITION":"GM"},{"LEVEL":5,"POSITION":"GMH"}]
let arr2 = [{"EMAIL":"test1@stc.com","POSITION":"GM"},
            {"EMAIL":"test2@stc.com","POSITION":"GMH"},
            {"EMAIL":"test3@stc.com","POSITION":"RGM"},
            {"EMAIL":"test3@CSR.COM.AU","POSITION":"GM"}]
            
let output = arr1.map(item => {
  item.Email = arr2.find(a => {
    return a.POSITION === item.POSITION
  }).EMAIL;
  
  return item;
});

console.log(output);

根据键搜索和更新数组

4 个答案: