Question

我正在尝试通过PHP中的表单上传文件。不幸的是文件上传不起作用。似乎未选择文件。下面是我的代码。我在下面复制了原始代码。

<html>
<body>
    <table>
            <form action="submit.php" method="POST" enctype="multipart/form-data">
        <tr>
            <td><label>Resume</label></td>
            <td><input type="file" name="cv" id="cv"></td>
        </tr>
        <tr></tr>
        <tr></tr>
        <tr>
            <td colspan="2"><button type="submit">Submit</button></td>
        </tr>
    </form>
    </table>
</body>

submit.php

<?php
if(isset($_POST['cv']))
    {
        $filename = $_FILES["cv"]["name"];
        echo $filename;

        $file_basename = substr($filename, 0, strripos($filename, '.')); // get file extention
        $file_ext = substr($filename, strripos($filename, '.')); // get file name
        $allowed_file_types = array('.doc','.docx','.rtf','.pdf');
        // Rename file
        $newfilename = $file_basename.$random.'_cv'. $file_ext;
        $filepath = "resume/" . $newfilename;
        if(move_uploaded_file($_FILES["cv"]["tmp_name"], $filepath))
        {
            echo "moved";
        }
        else
        {
            echo "not moved";
        }

    }
    else
    {
        echo "no file";
    }
?>

每当我运行此代码时，总是会收到错误no file。

任何人都可以帮助我找到我要去哪里的地方。

编辑1

我已经更新了合并评论的答案的代码。

submit.php

<?php
if(!empty($_FILES['cv']))
    {
        $filename = $_FILES["cv"]["name"];
        echo $filename;

        // $random = substr(number_format(time() * rand(),0,'',''),0,5);
        // $file_basename = substr($filename, 0, strripos($filename, '.')); // get file extention
        // $file_ext = substr($filename, strripos($filename, '.')); // get file name
        // $allowed_file_types = array('.doc','.docx','.rtf','.pdf');
        // // Rename file
        // $newfilename = $file_basename.$random.'_cv'. $file_ext;
        // $filepath = "resume/" . $newfilename;
        // if(move_uploaded_file($_FILES["cv"]["tmp_name"], $filepath))
        // {
        //     echo "moved";
        // }
        // else
        // {
        //     echo "not moved";
        // }

    }
    else
    {
        echo "no file";
    }
  ?>

现在，我只是在注释文件移动代码，并试图获取文件名。它仍然显示no file错误

Answer 1

您正在使用POST进行提交，但是您需要测试文件字段是否存在并且不为空-因此本质上您要测试isset( $_FILES['cv'] )等〜或可以使用!empty()进行测试如果已设置并且其限定值不等于零或null等

<?php

    $random=uniqid();
    $status=false;

    if( !empty( $_FILES['cv'] ) ){
        $obj=(object)$_FILES['cv'];
        $name=$obj->name;
        $tmp=$obj->tmp_name;
        $ext=strtolower( pathinfo( $name, PATHINFO_EXTENSION ) );
        $allowed=array('doc','docx','rtf','pdf');

        if( is_uploaded_file( $tmp ) && in_array( $ext, $allowed ) ){
            $filename=basename( $name ) . $random . '_cv.' . $ext;
            $filepath='resume/' . $filename;

            $status=move_uploaded_file( $tmp, $filepath );
        }
        echo $status ? 'moved' : 'not moved';
    } else {
        echo 'bogus';
    }

?>

一个有效的例子

<!DOCTYPE html>
<html>
    <head>
        <title>PHP: Upload resumé</title>
        <meta charset='utf-8' />
    </head>
    <body>
        <form method='post' enctype='multipart/form-data'>
            <input type='file' name='cv' />
            <input type='submit' />
        </form>
        <?php
            if( $_SERVER['REQUEST_METHOD']=='POST' ){

                $directory='c:/temp/resume';
                if( !file_exists( $directory ) ) mkdir( $directory, 0777, true );

                $random=uniqid();
                $status=false;

                if( !empty( $_FILES['cv'] ) ){

                    $obj=(object)$_FILES['cv'];
                    $name=$obj->name;
                    $tmp=$obj->tmp_name;
                    $ext=strtolower( pathinfo( $name, PATHINFO_EXTENSION ) );
                    $allowed=array('doc','docx','rtf','pdf');



                    if( is_uploaded_file( $tmp ) && in_array( $ext, $allowed ) ){

                        $filename=basename( $name ) . $random . '_cv.' . $ext;

                        $filepath=$directory . '/' . $filename;

                        $status=move_uploaded_file( $tmp, $filepath );
                    }

                    echo $status ? 'moved' : 'not moved';
                }
            }
        ?>
    </body>
</html>

Answer 2

只需更改Submit.php文件

 if (isset($_FILES['cv']['tmp_name']) && !empty($_FILES['cv']['tmp_name'])) {

    $random = rand(11111, 999999);
    $filename = $_FILES["cv"]["name"];
    //echo $filename;

    $file_basename = substr($filename, 0, strripos($filename, '.')); // get file extention
    $file_ext = substr($filename, strripos($filename, '.')); // get file name

    $allowed_file_types = array('.doc','.docx','.rtf','.pdf');
    // Rename file
    $newfilename = $file_basename.$random.'_cv'. $file_ext;
    $filepath = "resume/" . $newfilename;
    if(in_array($file_ext, $allowed_file_types)){
        if(move_uploaded_file($_FILES["cv"]["tmp_name"], $filepath))
        {
            echo "moved";
        }
        else
        {
            echo "Not moved";
        }
    }else{
       echo "File type invalid";
    }


}
else
{
    echo "no file";
}

完成

Answer 3

您应该首先查找可能的错误，如下所示：

if (UPLOAD_ERR_OK == $_FILES["cv"]["error"]) {
    $tmp_name = $_FILES["cv"]["tmp_name"];
    $real_name = basename($_FILES["cv"]["name"]);
    move_uploaded_file($tmp_name, "resume/{$real_name}");
} else {
    // process the file upload errors here
    var_dump($_FILES["cv"]["error"]);
}

寻找错误。例如，可能有UPLOAD_MAX_FILESIZE或POST_MAX_SIZE限制（请参见here）。

文件上传enctype = multipart / form-data在php中不起作用

3 个答案: