Question

通过API调用，我收到如下响应

[
  {
    stationId: "10"
    name: "Jinbaolai"
    group: {id: "18", stationGroupName: "Ali"}
  },
  {
    stationId: "13"
    name: "Stack"
    group: {id: "18", stationGroupName: "Ali"}
  },
  {
    stationId: "20"
    name: "Overflow"
    group: {id: "19", stationGroupName: "Baba"}
  }

]

如您所见，前两个记录包含相同的组。我想根据分组对这些数据进行分组。例如，它看起来应该像这样

[
  {
    groupId: "18",
    groupName : "Ali",
    stations : [
                 {
                  stationId: "10",
                  name: "Jinbaolai"
                 },
                 {
                  stationId: "13",
                  name: "Stack"
                 }
               ]

  },
  {
    groupId: "19",
    groupName : "Baba",
    stations : [
                 {
                  stationId: "20",
                  name: "Overflow"
                 },
               ]

  }

]

我想在化简器中进行分组逻辑，在那里我还设置了问题开始处显示的完整数据数组。

            case EVC_SUCCESS:
            return {
                ...state,
                chargingStations: action.evcData.chargingStations,
                chargingStationGroups: //This is where my logic should go. ('action.evcData.chargingStations' is the initial data array)
                tableLoading: false
            }

我该怎么做？我尝试使用filter进行尝试，但未成功。

Answer 1

执行此操作的最好方法是使用Array.prototype.reduce()

Reduce 是一种聚合函数，您可以在其中放入一些东西并获得单个的返回值。

像我使用{}一样，最后一个参数可能会有一个起始值。签名为reduce(fn, startingValue)，其中fn是一个带有两个参数aggregate和currentValue的函数，在此您最后返回聚合。

const groupData = (data)=> {

    return Object.values(data.reduce((group,n)=>{
    if (!group[n.group.id]){
        group[n.group.id] = {
      groupId:n.group.id,
      groupName: n.group.stationGroupName,
      stations:[]}
    } 
    group[n.group.id].stations.push({
      stationID: n.stationId,
      name: n.name
    })
    return group;
  }, {}))

}

这里是fiddle

Answer 2

一个简单的JS算法可以为您完成

const list = [
  {
    stationId: "10",
    name: "Jinbaolai",
    group: {id: "18", stationGroupName: "Ali"}
  },
  {
    stationId: "13",
    name: "Stack",
    group: {id: "18", stationGroupName: "Ali"}
  },
  {
    stationId: "20",
    name: "Overflow",
    group: {id: "19", stationGroupName: "Baba"}
  }

];
const groups = {};

list.forEach((item) => {
  const groupId = item.group.id;
  const group = groups[groupId] || {groupId: groupId, groupName: item.group.stationGroupName, stations: []};

  group.stations.push({stationId: item.stationId, name: item.name});
  groups[groupId] = group;
});

const groupedArray = Object.keys(groups).map((groupId) => groups[groupId]);

console.log(groupedArray); // This will be the output you want

Answer 3

我认为链接多个功能会起作用。

const stations = [
  {
    "stationId": 10,
    "name": "Jinbaolai",
    "group": {"id": "18", "stationGroupName": "Ali"}
  },
  {
    "stationId": 13,
    "name": "Stack",
    "group": {"id": 18, "stationGroupName": "Ali"}
  },
  {
    "stationId": 20,
    "name": "Overflow",
    "group": {"id": "19", "stationGroupName": "Baba"}
  }
]
const groups = _.chain(stations)
.groupBy((station) => { return station.group.id })
.map((values, key) => { 
  return {
    "groupId": _.first(values).group.id,
    "groupName": _.first(values).group.id,
    "stations": _.map(values,(value)=>{ return { "stationId": value.stationId, "name": value.name   } })
  }
})
console.log("groups",groups)

<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.15/lodash.min.js"></script>

根据ID对数组数据进行分组

3 个答案: