Question

我在数据库中输入0000-00-00的日期是dd-mm-yyyy格式，我也应该怎么做才能以dd-mm-yyyy格式获取SQL？

这是我的代码，我在https://youtu.be/r_JW1PDZlZo上观看了YouTube视频，做了日期格式化部分

我试图将其与已经完成的代码合并

我是PHP的新手，不知道如何更改它们，请以一种简单的方式逐步重播

<html>
<head>
    <h4 style="color:green;">ADD YOUR DETAILS BELOW </h4>

    <script src="https://kit.fontawesome.com/d3d5464d46.js" crossorigin="anonymous"></script>

    <script type="text/javascript">
        $(function() {
            $("#datepicker").datepicker({
                dateFormat: "dd-mm-yy"
            }).val()
        });
    </script>

    <body style="background: url(img/too.jpg); background-repeat;background-size:100% 100%">

        <a href="index.php">
            <button <i class="fas fa-home"></i>&nbsp; RETURN</button>
        </a>
        <br></br>
        <br></br>

        <form action="add.php" method="post" name="form1">

            <table>
                <link rel="stylesheet" type="text/css" href="style.php?" />

                <tr>
                    <td>Company Name</td>
                    <td>
                        <input type="text" name="company_name" placeholder="companie's name..">
                    </td>
                </tr>

                <tr>
                    <td>Client Name </td>
                    <td>
                        <input type="text" name="client_name" placeholder="your's name..">
                    </td>
                </tr>

                <tr>
                    <td>Date of entry</td>
                    <td>
                        <input type="date" name="date_of_entry" placeholder="DD/MM/YYYY">
                    </td>
                </tr>

                <tr>
                    <td>Phone</td>
                    <td>
                        <input type="text" name="phone" placeholder="phone no">
                    </td>
                </tr>
                <p>

                    <tr>
                        <td></td>
                        <td>
                            <button type="submit" name="submit" value="ADD" <i class="fas fa-plus">
                                </i>&nbsp;ADD</button>
                        </td>
                    </tr>

            </table>
        </form>

        <?php    
        if(isset($_POST['submit']))
        {
            $comp_nam =$_POST['company_name'];
            $cli_nam =$_POST['client_name'];
            $dat=$_POST['date_of_entry'];
            $phn=$_POST['phone'];

            $resulto= explode('-','/' $dat);
            $date=$resulto[2];
            $month=$resulto[1];
            $year=$resulto[0];

            echo $dat=$date.'-'.$month.'-'.$year;

            include_once"config.php";

            $result= mysqli_query($conn,"INSERT INTO information (company_name,client_name,date_of_entry,phone) VALUES('$comp_nam','$cli_nam','$dat','$phn')")  or die(mysqli_error($conn));

            header("location:index.php");

            echo "User added successfully";    
        }    
        ?>
    </body>
</html>

请有人尽快回答我

Answer 1

此
echo $ dat = $ date .'-'。$ month .'-'。$ year;

应该是

echo $ dat = $ year .'-'。$ month .'-'。$ date;

我在将日期格式化为dd-mm-yyyy时遇到问题

1 个答案: