无法从mapsDispatchToProps访问“道具”

时间:2019-12-20 22:46:14

标签: javascript reactjs redux

我正在尝试通过redux动作将输入值从组件传递给函数。我能够在功能道具中获得价值。但是,道具没有传递到return dispatch =>函数中。有什么办法可以实现这个目标?

actions.js

function fetchData(url){
  return fetch(url)
            .then(res => res.json())
            .catch(console.log())
}

export function getFilteredCharacters(input) {
  console.log(input); //Shows props in console
  return (dispatch) => {

    console.log(chars); //Doesn't show props in console
    for (let i=1; i<=9; i++) {
      requests.push(fetchData('https://swapi.co/api/people/?page=' + i));
    }

    Promise.all(requests)
    .then(data => {
      let charactersAll = [];
      let characterFiltered = [];
      for (let i=0; i<=8; i++) {
        charactersAll.push(...data[i].results);
      }
      for (let i=0; i < charactersAll.length; i++) {
        if (charactersAll[i].name.includes(input)) { // This is where I need the props.
          characterFiltered.push(charactersAll[i]);
        }
      }
      dispatch(setFilteredCharacters(characterFiltered));
    })
  }
}

export function setFilteredCharacters(characterFiltered) {
  return {
    type: SET_CHARACTERS_FILTERED,
    characterFiltered
  }
}

components / FilterInput.js

import React from 'react';
import { connect } from 'react-redux';
import { getFilteredCharacters } from '../reducer/character/actions';


const FilterInput = ({ setFilter }) => {

  return (
    <div class="input-group">
      <div class="input-group-prepend">
        <span class="input-group-text">Name</span>
      </div>
      <input type="text" aria-label="Name" className="form-control" onChange={e => getFilteredCharacters(e.target.value)} />
    </div>
  )
};

const mapDispatchToProps = dispatch => ({
  getFilteredCharacters(input) {}
});

export default connect(null, mapDispatchToProps)(FilterInput);

感谢任何人的见识。

1 个答案:

答案 0 :(得分:3)

这是正确的方法

const mapDispatchToProps = dispatch => ({
  getFilteredCharacters: (input)=>dispatch(getFilteredCharacters(input))
});

或者简单地

const mapDispatchToProps = {getFilteredCharacters}

当前,您正在直接在FilterInput内部调用getFilteredCharacters。为此添加道具参数

const FilterInput = ({ setFilter, getFilteredCharacters }) => {
//...
}