我有两个收藏。我正在尝试将集合2的文档添加到集合1中,如果集合2中的1号和2号在集合1中指定的某个范围内。集合1中的FYI ObjectId和集合2中的ObjectId引用两个不同的项/产品,因此我无法加入此ID上的两个收藏夹。
集合1中的示例文档
{'_id': ObjectId('4321'),
'number1_lb': 61.205672407820025,
'number1_ub': 61.24170844385606,
'number2_lb': -149.75074963516136,
'number2_ub': -149.71471359912533}
集合2中的示例文档
{'_id': ObjectId('1234'),
'number1': 1.282298,
'number2': 103.8475}
我想要输出:
{'_id': ObjectId('4321'),
'number1_lb': 61.205672407820025,
'number1_ub': 61.24170844385606,
'number2_lb': -149.75074963516136,
'number2_ub': -149.71471359912533,
'recs': [ObjectId('3456'), ObjectId('4567'),...]
我认为带有管道的查找阶段会起作用。我的代码当前如下:
{"$lookup":{
"from": "Collection 2",
"let":{
"number1_lb":"$number1_lb",
"number1_ub":"$number1_ub",
"number2_lb":"$number2_lb",
"number2_ub":"$number2_ub"
},
"pipeline": [
{"$match":
{"$expr":
{"$and":[
{"$gte":["$number1","$$number1_lb"]},
{"$gte":["$number2","$$number2_lb"]},
{"$lte":["$number1","$$number1_ub"]},
{"$lte":["$number2","$$number2_ub"]}
]}}}
],
"as": "recs"
}}
但是运行上面的命令没有任何输出。我做错什么了吗?
答案 0 :(得分:1)
我运行了它,看起来效果很好;但是我不得不在coll1
中调整您的输入数据,因为它不符合$match
的条件。
from pymongo import MongoClient
from bson.json_util import dumps
db = MongoClient()["testdatabase"]
# Data Setup
db.coll1.replace_one({"_id": "4321"}, {"_id": "4321", "number1_lb": -61.205672407820025, "number1_ub": 61.24170844385606, "number2_lb": -149.75074963516136, "number2_ub": 149.71471359912533}, upsert=True)
db.coll2.replace_one({"_id": "1234"}, {"_id": "1234", "number1": 1.282298, "number2": 103.8475}, upsert=True)
# Run the aggregation
results = db.coll1.aggregate([
{"$lookup": {
"from": "coll2",
"let": {
"number1_lb": "$number1_lb",
"number1_ub": "$number1_ub",
"number2_lb": "$number2_lb",
"number2_ub": "$number2_ub"
},
"pipeline": [
{"$match":
{"$expr":
{"$and": [
{"$gte": ["$number1", "$$number1_lb"]},
{"$gte": ["$number2", "$$number2_lb"]},
{"$lte": ["$number1", "$$number1_ub"]},
{"$lte": ["$number2", "$$number2_ub"]}
]}}}
],
"as": "recs"
}}
])
# pretty up the results
print(dumps(results, indent=4))
给予:
[
{
"_id": "4321",
"number1_lb": -61.205672407820025,
"number1_ub": 61.24170844385606,
"number2_lb": -149.75074963516136,
"number2_ub": 149.71471359912533,
"recs": [
{
"_id": "1234",
"number1": 1.282298,
"number2": 103.8475
}
]
}
]
答案 1 :(得分:0)
您要使用$lookup
和$project
>
{
$lookup: {
from: "Collection2",
localField: [Foreign Field of the Collection1],
foreignField: [Principal field of the foreign collection here Collection2],
as: "nameJoint"
}
},
{$project: {
"newFieldName":
}},
但是要在两个文档之间建立一个联合,在这两个文档之间要有一个公共字段。我不确定这种情况是否会发生,否则我会误解。
($lookup
是noSQL中的SQL联合)