我想从下表中选择:
PostTable
feed dateinserted count
box1 2011-05-28 11:00 1000
box2
box3
box4
box5
box6
前一天的记录总数,即1,3和5,即 我需要根据我需要的东西来选择我需要检索的总数,例如它可以是box4和方框5 ......不是特别奇怪甚至......我希望这会让它更清晰......
我对所有记录的所有内容:
select sum(count) as [total] from PostTable where Cast(dateinserted as DATE) =
CAST(getdate()-1 as DATE)
答案 0 :(得分:2)
SELECT feed, SUM(count) AS total FROM PostTable
WHERE Cast(dateinserted as DATE) = CAST(getdate()-1 as DATE) AND feed IN ('box1', 'box3', 'box4')
GROUP BY feed
答案 1 :(得分:0)
SELECT SUM(count) AS Total FROM PostTable WHERE CONVERT(date, dateinserted, 101)=CONVERT(DATE, DATEADD(DAY, -1, GETDATE()), 101) AND feed % 2=1
编辑后,查询将如下所示:
;with temp as(
select ROW_NUMBER() OVER (ORDER BY feed) AS RowNum, * from PostTable)
SELECT SUM(count) AS Total FROM temp WHERE CONVERT(date, dateinserted, 101)=CONVERT(DATE, DATEADD(DAY, -1, GETDATE()), 101) AND RowNum % 2=1
请注意WITH语句开头的分号。查询必须成功运行。
答案 2 :(得分:0)
对于随机奇数
,这可能对您有所帮助<强> ID阿略 1 2 3 4 五 6 7 8 9 强>
declare @input varchar(10)
set @input = 1
while @input < = 9
begin
select id from emp where id = @input
set @input = @input + 2
end