我们的应用程序中有一个Toast组件,这为我们的测试增加了相当的脆弱性。 Toast组件显示一个动画视图4秒钟,然后消失。在许多测试中,我需要检查View内部的消息是什么,以便继续进行测试。
吐司组件通过以下代码实现:
// @flow
import * as React from "react"
import { StyleSheet, View, Animated, Dimensions, Text } from "react-native"
import type {
TextStyle,
ViewStyle,
} from "react-native/Libraries/StyleSheet/StyleSheet"
import type AnimatedValue from "react-native/Libraries/Animated/src/nodes/AnimatedValue"
import type { CompositeAnimation } from "react-native/Libraries/Animated/src/AnimatedImplementation"
import { AnimationConstants } from "constants/animations"
const styles = StyleSheet.create({
container: {
position: "absolute",
left: 0,
right: 0,
elevation: 999,
alignItems: "center",
zIndex: 10000,
},
content: {
backgroundColor: "black",
borderRadius: 5,
padding: 10,
},
text: {
color: "white",
},
})
type Props = {
style: ViewStyle,
position: "top" | "center" | "bottom",
textStyle: TextStyle,
positionValue: number,
fadeInDuration: number,
fadeOutDuration: number,
opacity: number,
}
type State = {
isShown: boolean,
text: string | React.Node,
opacityValue: AnimatedValue,
}
export const DURATION = AnimationConstants.durationShort
const { height } = Dimensions.get("window")
export default class Toast extends React.PureComponent<Props, State> {
static defaultProps = {
position: "bottom",
textStyle: styles.text,
positionValue: 120,
fadeInDuration: AnimationConstants.fadeInDuration,
fadeOutDuration: AnimationConstants.fadeOutDuration,
opacity: 1,
}
isShown: boolean
duration: number
callback: Function
animation: CompositeAnimation
timer: TimeoutID
constructor(props: Props) {
super(props)
this.state = {
isShown: false,
text: "",
opacityValue: new Animated.Value(this.props.opacity),
}
}
show(text: string | React.Node, duration: number, callback: Function) {
this.duration = typeof duration === "number" ? duration : DURATION
this.callback = callback
this.setState({
isShown: true,
text: text,
})
this.animation = Animated.timing(this.state.opacityValue, {
toValue: this.props.opacity,
duration: this.props.fadeInDuration,
useNativeDriver: true,
})
this.animation.start(() => {
this.isShown = true
this.close()
})
}
close(duration?: number) {
const delay = typeof duration === "undefined" ? this.duration : duration
if (!this.isShown && !this.state.isShown) return
this.timer && clearTimeout(this.timer)
this.timer = setTimeout(() => {
this.animation = Animated.timing(this.state.opacityValue, {
toValue: 0.0,
duration: this.props.fadeOutDuration,
useNativeDriver: true,
})
this.animation.start(() => {
this.setState({
isShown: false,
})
this.isShown = false
if (typeof this.callback === "function") {
this.callback()
}
})
}, delay)
}
componentWillUnmount() {
this.animation && this.animation.stop()
this.timer && clearTimeout(this.timer)
}
render() {
const { isShown, text, opacityValue } = this.state
const { position, positionValue } = this.props
const pos = {
top: positionValue,
center: height / 2,
bottom: height - positionValue,
}[position]
if (isShown) {
return (
<View style={[styles.container, { top: pos }]}>
<Animated.View
style={[
styles.content,
{ opacity: opacityValue },
this.props.style,
]}
>
{React.isValidElement(text) ? (
text
) : (
<Text style={this.props.textStyle}>{text}</Text>
)}
</Animated.View>
</View>
)
}
return null
}
}
通常,我们将烤面包消息显示4秒钟,但我决定在e2e测试中将其显示1.5秒钟,以便更快地完成。
我正在测试是否存在烤面包:
await expect(element(by.text(text))).toBeVisible()
await waitFor(element(by.text(text))).toBeNotVisible().withTimeout(2000)
但是,排毒常常在“ toBeVisible”失败。我可以在屏幕上看到该消息,但由于某种原因排毒将其丢失。
我应该将消息保留在屏幕上以便排毒检测到的最短时间是什么?
答案 0 :(得分:1)
我仍然不确定是否有更好的方法,但是我找到了目前对我们有用的方法。
我们没有在e2e测试中自动隐藏吐司,而是模拟了模态组件以显示并保持可见,直到点按为止。
排毒一次见到我们点击它的元素,将其关闭并继续进行测试。