查找行之间的重复值并将行与一个或多个重复值组合在一起

Question

我有一个像这样的数据集：

   shop_code  pick_tel     tel     account    mail  stk
0          A    123456  123456   123456789   sfsdf  123
1          B    234567  234567  9876543210   dfndf  456
2          C    789456  789456  1579624325    sldf  789
3          D    258643  258643  1112299555  mvklsd  234
4          F    123456  123456  1487658794   sfsdf  476
5          Y    159753  159753  2369874568  lsdnfg  123
6          U    753951  753951   123456789  klsdjv  345
7          O    234567  234567  1234587963   dfndf  456
8          P    951357  951357  1579624325    skse  678
9          A    951357  123456   123456789   sfsdf  123
10         B    654798  234567  9876543210   dfndf  456
11         C    121347  789456  1579624325    sldf  789
12         D    123485  258643  1112299555  mvklsd  234
13         A    753951  123456   123456789   sfsdf  123
14         O    657543  234567  1234587963   dfndf  456
15         A    245213  123456   123456789   sfsdf  123
16         O    753951  234567  1234587963   dfndf  456
17         P    124856  951357  1579624325    skse  678

我的代码是：

def check_trung(df):
    dict_diachi = {}


    dict_mashop = {}
    dict_mail = {}
    dict_sdt = {}
    dict_stk = {}
    dict_picktel = {}
    dict_total = []

    group = {}

    group_id = 1
    for i, row in df.iterrows():
        # print("row:", i, row[0])
        diachi, mashop, picktel, mail, sdt, stk = row

        if diachi in dict_diachi:
            group_id_2 = dict_diachi[diachi]
            group[group_id_2].append(i)
        elif mashop in dict_mashop:
            group_id_2 = dict_mashop[mashop]
            group[group_id_2].append(i)
        elif picktel in dict_picktel:
            group_id_2 = dict_picktel[picktel]
            group[group_id_2].append(i)
        elif mail in dict_mail:
            group_id_2 = dict_mail[mail]
            group[group_id_2].append(i)
        elif sdt in dict_sdt:
            group_id_2 = dict_sdt[sdt]
            group[group_id_2].append(i)
        elif stk in dict_stk:
            group_id_2 = dict_stk[stk]
            group[group_id_2].append(i)
        else:
            group[group_id] = [i]

            dict_diachi[diachi] = group_id
            dict_mashop[mashop] = group_id
            dict_picktel[picktel] = group_id
            dict_mail[mail] = group_id
            dict_sdt[sdt] = group_id
            dict_stk[stk] = group_id
            group_id += 1
    for i, item in group.items():  ## Heading ##
        print("----------")
        print("item:", i, item)

check_trung(df)

结果是：

项目：1 [0、4、5、6、9、13、15]

项目：2 [1、7、10、14、16]

项目：3 [2，8，11，17]

项目：4 [3，12]

项目1缺少8，因为8和9具有相同的“ picktel”列值。谁能告诉我为什么他们不在一起。

与另一行至少共享一个其他值的每一行都应分组在一起。