我可以告诉外部函数从其本地函数内部返回吗？

Question

我有一个IEnumerator，我需要在函数内部进行一些检查，如果其中一些检查失败，则需要进行一些维护，然后退出IEnumerator。但是，当我将yield break写入内部函数时，它认为我正在尝试从该内部函数返回。

我想我可以在内部函数调用之后写private IEnumerator OuterFunction() { //bla bla some code //some check: if (!conditionA) Fail(); //if didn't fail, continue normal code //another check: if (!conditionB) Fail(); //etc.... //and here's the local function: void Fail() { //some maintenance stuff I need to do //and after the maintenance, exit out of the IEnumerator: yield break; //^ I want to exit out of the outer function on this line //but the compiler thinks I'm (incorrectly) returning from the inner function Fail() } } ，但我想保持DRY。

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Answer 1

您需要将产量中断放在OuterFunction（）中。参见What does "yield break;" do in C#?

private IEnumerator OuterFunction()
{
    //bla bla some code

//some check:
if (!conditionA){
    Fail();
    yield break;
}

//if didn't fail, continue normal code

//another check:
if (!conditionB){
    Fail();
    yield break;
}

//etc....

//and here's the local function:
void Fail()
{
    //some maintenance stuff I need to do

    //and after the maintenance, exit out of the IEnumerator:

    //^ I want to exit out of the outer function on this line
    //but the compiler thinks I'm (incorrectly) returning from the inner function Fail()
}
}