我想基于一组包含过滤条件的数组来过滤对象。它基本上可以工作,直到其中一个过滤器数组包含多个项。这是代码:
// the filters
const filters = {
"eyeColor": ["blue"],
"gender": ["male"],
"age": ["33"],
"tags": ["d3js", "vuejs"] // multiple terms in the filter array breaks the code (returns empty array)
}
// the data
const users = [
{
"age": "33",
"eyeColor": "blue",
"tags": "d3js, max, grotesk",
"gender": "male",
},
{
"age": "31",
"eyeColor": "blue",
"tags": "vuejs, adrian, serif",
"gender": "male",
},
{
"age": "37",
"eyeColor": "brown",
"tags": "vuejs, max, mono, d3js",
"gender": "female",
},
{
"age": "33",
"eyeColor": "blue",
"tags": "vuejs, markus, grotesk",
"gender": "male",
},
]
// the filter function
let results = users.filter(function (object) {
return Object.entries(filters).every(function ([key, value]) {
return value.every(function (filter) {
return object[key].includes(filter)
})
})
});
console.log(results);
我得到一个空数组,而预期结果将是:
{
"age": "33",
"eyeColor": "blue",
"tags": "d3js, max, grotesk",
"gender": "male",
},
{
"age": "33",
"eyeColor": "blue",
"tags": "vuejs, markus, grotesk",
"gender": "male",
}
如何获得预期的结果?
答案 0 :(得分:2)
代码使用
return value.every(function (filter) ...
// ^^^^^
,但是您不希望匹配允许数组中所有标签的 all ,仅匹配some
( any ):
return value.some(function (filter) ...
// ^^^^
这是一个示范:
const filters = { "eyeColor": ["blue"], "gender": ["male"], "age": ["33"], "tags": ["d3js", "vuejs"] }
const users = [{ "age": "33", "eyeColor": "blue", "tags": "d3js, max, grotesk", "gender": "male", }, { "age": "31", "eyeColor": "blue", "tags": "vuejs, adrian, serif", "gender": "male", }, { "age": "37", "eyeColor": "brown", "tags": "vuejs, max, mono, d3js", "gender": "female", }, { "age": "33", "eyeColor": "blue", "tags": "vuejs, markus, grotesk", "gender": "male", }, ];
const filterEntries = Object.entries(filters);
const results = users.filter(user =>
filterEntries.every(([key, permitted]) =>
permitted.some(e => user[key].includes(e))
)
);
console.log(results);