Question

我正在使用react挂钩构建项目，但在下面出现此错误。

Uncaught Error: Invalid hook call. Hooks can only be called inside of the body of a function component. This could happen for one of the following reasons:
1. You might have mismatching versions of React and the renderer (such as React DOM)
2. You might be breaking the Rules of Hooks
3. You might have more than one copy of React in the same app

这是下面的代码

const authRequest = (e: any) => {
  e.preventDefault();
  alert('Error!')
  const [authRequestState, authRequestTrue] = React.useState(false)
  authRequestTrue(true)
}


const renderFormikForm = () => {
  return (
    <Formik initialValues={{country: '', number: ''}} onSubmit={(values) => {submitForm(values)}}>
      {({ values, errors, touched, handleChange, handleBlur}) => (
        <form>
          <div className='input-box'>
            <p className='input'>
              <input type='email' name='email' placeholder='emial' value='libeto@commontown.co'/>
            </p>
            <p className='input'>
              <input type='number' name='number' placeholder='number' value={values.number} onChange={handleChange} style={{width: '50%'}} />
              <button onClick={(e) => authRequest(e)}><em><a>Click!!!</a></em></button>
            </p>
          </div>
        </form>
      )}
    </Formik>
  )
}

因此，基本上，功能组件会呈现 renderFormikForm组件，当我单击按钮（例如Click !!!）时，onClick会触发authRequest函数，但是状态发生了变化，它给了我我上面提到的错误

Answer 1

只能在函数组件内部创建挂钩。您需要在功能组件内使用useState 。

将您的代码更新为以下内容：


const renderFormikForm = () => {
  const [authRequestState, authRequestTrue] = React.useState(false)

  const authRequest = (e: any) => {
    e.preventDefault();
    alert('Error!')
    authRequestTrue(true)
  }
  return (
    <Formik initialValues={{country: '', number: ''}} onSubmit={(values) => {submitForm(values)}}>
      {({ values, errors, touched, handleChange, handleBlur}) => (
        <form>
          <div className='input-box'>
            <p className='input'>
              <input type='email' name='email' placeholder='emial' value='libeto@commontown.co'/>
            </p>
            <p className='input'>
              <input type='number' name='number' placeholder='number' value={values.number} onChange={handleChange} style={{width: '50%'}} />
              <button onClick={(e) => authRequest(e)}><em><a>Click!!!</a></em></button>
            </p>
          </div>
        </form>
      )}
    </Formik>
  )
}

或者您也可以按如下方式重新编写它：

const authRequest = (e: any, authRequestTrue) => {
  e.preventDefault();
  alert('Error!')
  authRequestTrue(true)
}
const renderFormikForm = () => {
  const [authRequestState, authRequestTrue] = React.useState(false)

  return (
    <Formik initialValues={{country: '', number: ''}} onSubmit={(values) => {submitForm(values)}}>
      {({ values, errors, touched, handleChange, handleBlur}) => (
        <form>
          <div className='input-box'>
            <p className='input'>
              <input type='email' name='email' placeholder='emial' value='libeto@commontown.co'/>
            </p>
            <p className='input'>
              <input type='number' name='number' placeholder='number' value={values.number} onChange={handleChange} style={{width: '50%'}} />
              <button onClick={(e) => authRequest(e, authRequestTrue)}><em><a>Click!!!</a></em></button>
            </p>
          </div>
        </form>
      )}
    </Formik>
  )
}

后一种更接近所提到的代码。

希望有帮助。如有任何疑问，请回复。

反应挂钩，发生无效的挂钩调用错误

1 个答案: