您好,我需要选择仅包含不同值的listagg列。不幸的是,我使用的是oracle 18.c,它不支持直接不同的选项,因此我可能必须使用嵌套选择(不确定吗?)。我有以下SQL查询,我需要将“ adrml.email”列与不同的值。
select distinct
c.trader_transact
, t.trader_descr
, d.third
, d.f_name
, d.def_phone
, d.def_mail
, d.f_city
, d.country_descr
, d.f_street
, con.first_name
, con.last_name
, adrph.formated_phone_nr
, link.adr
, link.contact
,adrdet.dt
,adrdet.street Contact_Street
,adrdet.post_code
,adrdet.city
,adrdet.country
,adrml.email
,LISTAGG(
adrml.email,
' / '
) WITHIN GROUP(
ORDER BY
d.third
)
from thr_v_third d
join tra_contract c on d.third = c.customer or d.third = c.supplier
join tra_trader t on t.trader = c.trader_transact
join thr_v_adr_lnk_contact link on link.third = d.third --and link.type = 1 and link.default_contact = 1
join adr_contact con on con.adr = link.adr and con.contact = link.contact
join adr_address_det adrdet on adrdet.adr = link.adr and adrdet.last = 1
left join adr_mail adrml on link.adr = adrml.adr and con.contact = adrml.contact and adrml.deflt = 1
left join adr_v_phones adrph on adrph.adr = link.adr and adrph.contact = link.contact and adrph.deflt = 1 and adrph.type = 1
where t.trader = 32
group by
c.trader_transact
, t.trader_descr
,d.third
, d.f_name
, d.def_phone
, d.def_mail
, d.f_city
, d.country_descr
, d.f_street
, link.adr
, link.contact
, con.first_name
, con.last_name
,adrdet.dt
,adrdet.street
,adrdet.post_code
,adrdet.city
,adrdet.country
,adrml.email
, adrph.formated_phone_nr
order by d.third
到目前为止,我在listagg列中收到重复的电子邮件。我该如何清除呢?
答案 0 :(得分:1)
这是您拥有的:
SQL> select d.dname,
2 listagg(e.job, ', ') within group (order by e.job) jobs
3 from dept d join emp e on e.deptno = d.deptno
4 group by d.dname;
DNAME JOBS
-------------- ------------------------------------------------------------
ACCOUNTING CLERK, MANAGER, PRESIDENT
RESEARCH ANALYST, ANALYST, CLERK, CLERK, MANAGER
SALES CLERK, MANAGER, SALESMAN, SALESMAN, SALESMAN, SALESMAN
这就是您想要的:
SQL> select x.dname,
2 listagg(x.job, ', ') within group (order by x.job) jobs
3 from (select distinct d.dname,
4 e.job
5 from dept d join emp e on e.deptno = d.deptno
6 ) x
7 group by x.dname;
DNAME JOBS
-------------- ------------------------------------------------------------
ACCOUNTING CLERK, MANAGER, PRESIDENT
RESEARCH ANALYST, CLERK, MANAGER
SALES CLERK, MANAGER, SALESMAN
SQL>
是的-首先找到不同的值,然后listagg
。
答案 1 :(得分:0)
您可以按以下方式使用REGEXP_REPLACE
和XMLAGG
删除重复项:
SQL> with table1(req) as 2 (SELECT 'TEJASH' FROM DUAL UNION ALL 3 SELECT 'RIDDHI' FROM DUAL UNION ALL 4 SELECT 'TEJASH' FROM DUAL UNION ALL 5 SELECT 'REKHA' FROM DUAL) 6 SELECT 7 REGEXP_REPLACE(RTRIM(XMLAGG(XMLELEMENT(E, REQ, ',').EXTRACT('//text()') 8 ORDER BY 9 REQ 10 ).GETCLOBVAL(), ','), '([^,]+)(,\1)+', '\1') AS LIST 11 FROM 12 TABLE1; LIST -------------------------------------------------------------------------------- REKHA,RIDDHI,TEJASH SQL>
使用XMLAGG
代替LISTAGG
的原因是为了避免出现4000个字符限制的问题。
还可以使用LISTAGG
来使用REGEXP_REPLACE
,如下所示:
SQL> with table1(req) as 2 (SELECT 'TEJASH' FROM DUAL UNION ALL 3 SELECT 'RIDDHI' FROM DUAL UNION ALL 4 SELECT 'TEJASH' FROM DUAL UNION ALL 5 SELECT 'REKHA' FROM DUAL) 6 SELECT 7 REGEXP_REPLACE( 8 LISTAGG(REQ, ',') WITHIN GROUP( 9 ORDER BY 10 REQ 11 ), '([^,]+)(,\1)+', '\1') AS LIST 12 FROM 13 TABLE1; LIST -------------------------------------------------------------------------------- REKHA,RIDDHI,TEJASH SQL>
干杯!