Question

我有两个数组，两个数组的索引都包含对象

$array1=array(1) { 
[0]=> object(stdClass) (3) {
    ["aid"]=> string(1) "1"
    ["a_number"]=> string(1) "0" 
    ["id_of"]=> string(1) "1"  
    }
}


$array2=array(3) { 
[0]=> object(stdClass) (3) {
    ["id"]=> string(1) "1",
    ["number"]=> string(1) "0" ,
    ["flag"]=> string(1) "1" , 
    ["zflag"]=> string(1) "0" , 
    ["xflag"]=> string(1) "1"  
    } ,
    [1]=> object(stdClass) (3) {
    ["id"]=> string(1) "2",
    ["number"]=> string(1) "2" ,
    ["flag"]=> string(1) "2" , 
    ["zflag"]=> string(1) "0" , 
    ["xflag"]=> string(1) "1"  
    },
    [1]=> object(stdClass) (3) {
    ["id"]=> string(1) "3",
    ["number"]=> string(1) "3", 
    ["flag"]=> string(1) "3" , 
    ["zflag"]=> string(1) "0" , 
    ["xflag"]=> string(1) "1"  
    }
}

我想比较$id所有元素中$array2键的值和$id_of每个元素中$array1的值，如果不存在则返回$array1的元素。以下是我的代码，但它不起作用

public function unanswered($array1,$array2){
        if(!(empty($array2))){
            $unanswered_arrays=array();
            foreach($array1 as $b){
                foreach($array2 as $a){
                    if($b->id != $a->id_of){
                        array_push($unanswered_arrays,(object)$b);
                    }
                }
            }
            return $unanswered_arrays;
        }
        return $array1;
    }

Answer 1

如果您将函数用作unanswered($array1,$array2)，则在foreach循环中将$array1替换为$array2，反之亦然，或者通过unanswered($array2,$array1)代替。

Demo

数组索引的PHP对象键值比较

1 个答案: