Question

给出JSON，如：

{"thing": ["hello", "bye"], "other": {"hello": "myval"}}

我想要一个jq表达式，该表达式将数组中“ thing”下的第一个元素放在“ other”中查找。所以我做到了：

jq '.thing[0] as $tofind | .other.$tofind'

但我明白了

jq: error: syntax error, unexpected '$', expecting FORMAT or QQSTRING_START (Unix shell quoting issues?) at <top-level>, line 1:
.thing[0] as $tofind | .other.$tofind
jq: 1 compile error

我尝试了多种其他方法：

echo '{"thing": ["hello", "bye"], "other": {"hello": "myval"}}' | jq '.thing[0] as $tofind | .other.($tofind)'
jq: error: syntax error, unexpected '(', expecting FORMAT or QQSTRING_START (Unix shell quoting issues?) at <top-level>, line 1:
.thing[0] as $tofind | .other.($tofind)
jq: 1 compile error
echo '{"thing": ["hello", "bye"], "other": {"hello": "myval"}}' | jq '.thing[0] as $tofind | .other.[($tofind)]'
jq: error: syntax error, unexpected '[', expecting FORMAT or QQSTRING_START (Unix shell quoting issues?) at <top-level>, line 1:
.thing[0] as $tofind | .other.[($tofind)]
jq: 1 compile error
echo '{"thing": ["hello", "bye"], "other": {"hello": "myval"}}' | jq '.thing[0] as $tofind | .other.[$tofind]'
jq: error: syntax error, unexpected '[', expecting FORMAT or QQSTRING_START (Unix shell quoting issues?) at <top-level>, line 1:
.thing[0] as $tofind | .other.[$tofind]
jq: 1 compile error
echo '{"thing": ["hello", "bye"], "other": {"hello": "myval"}}' | jq '.thing[0] as $tofind | .other.["$tofind"]'
jq: error: syntax error, unexpected '[', expecting FORMAT or QQSTRING_START (Unix shell quoting issues?) at <top-level>, line 1:
.thing[0] as $tofind | .other.["$tofind"]
jq: 1 compile error
echo '{"thing": ["hello", "bye"], "other": {"hello": "myval"}}' | jq '.thing[0] as $tofind | .other."$tofind"'
null
echo '{"thing": ["hello", "bye"], "other": {"hello": "myval"}}' | jq '.thing[0] as $tofind | .other."($tofind)"'
null

我找到了select和to_entries的变通方法，但是我觉得必须有一种不错的方法来做到这一点，而我却不见了。

Answer 1

A() noexcept {}

Answer 2

您可以简单地写：

jq '.other[.thing[0]]'

使用jq变量（来自“ as”）查找键

2 个答案: