Question

select count(*) from MyTable where FREETEXT(LongDescription,'BOTH')      --Returns 0
select count(*) from MyTable where FREETEXT(LongDescription,'"*`BOTH`*"')    --Returns 0

select count(*) from MyTable where Contains(LongDescription,'BOTH')     --Returns 0 
select count(*) from MyTable where Contains(LongDescription,'"*`BOTH`*"') -- Returns 5

select count(*) from MyTable where LongDescription like '%BOTH%'   -- Returns 7040 

select count(*) from MyTable  where LongDescription like '%XXS%'        -- Returns 2473
select count(*) from MyTable  where FREETEXT(LongDescription,'"*XXS*"') -- Returns 2787
select count(*) from MyTable  where contains(LongDescription,'"*XXS*"') -- Returns 2411

我尝试了带有和不带有`以及“，*，％”的变体。由于BOTH是保留字，是否会阻止Contains或Freetext正常工作？我可以搜索其他单词，但即使如此我得到随机结果。

sys.fulltext_stopwords和sys.fulltext_stoplists为空。

我正在尝试模仿https://datatables.net/之类的搜索功能，在该功能中，搜索方式是以行分隔的每个字符串都存在于该行的至少1列中。我知道我可以这样做，但是如果他们都输入像BOTH这样的单词，那么它以某种方式返回0，是否值得使用？否则，我将创建一个查询构建器来创建类似这样的东西。

select count(*) from MyTable

where 
(SearchDescription like '%TEST%'      or
ShortDescription like '%TEST%' or
LongDescription  like '%TEST%') 
and 
(SearchDescription like '%BOTH%' or
ShortDescription like '%BOTH%' or
LongDescription  like '%BOTH%') 
and 
(SearchDescription like '%THREA%' or
ShortDescription like '%THREA%' or
LongDescription like '%THREA%')

如何在SQL FREETEXT查询中搜索单词“ BOTH”？

0 个答案: