刮擦如何立即从产量打印结果

Question

函数parse在第一页中抓取链接。函数parse_product在下一页抓取详细信息，并检查是否有要抓取的第三页。函数parse_finalreport在第3页中抓取详细信息。我面临的问题是第三函数parse_finalreport的输出最后一起打印。我想要这样的结果：

dfgcontactperson
year
abstract

dfgcontactperson
empty
empty

dfgcontactperson
year
abstract

但是我得到的结果是这样的：

dfgcontactperson

dfgcontactperson
empty
empty

dfgcontactperson

year
abstract
year
abstract

我的代码：

 def parse(self,response):
  for row in response.xpath('//div[contains(@class,"eintrag")]'):
        link = row.xpath('.//h2/a/@href').extract()
        link = ['https://gepris.dfg.de' + item + '?language=en' for item in link]
        for p in link:
            yield scrapy.Request(p,callback=self.parse_product)

def parse_product(self, response):
   dfgcontactperson = response.xpath('//div[@class="dfg_contact"]/span[@class="value"]/span/a/text()').extract()
   print(dfgcontactperson)
   finalreport = response.xpath('//ul[@class="tab1"]/li[@id="tabbutton2"]/a/@href').extract()
        finalreport = ['https://gepris.dfg.de' + item + '?language=en' for item in finalreport]
        if not finalreport:
            print('empty')
            print('empty')
        for x in finalreport:
            yield scrapy.Request(x,callback=self.parse_finalreport)

 def parse_finalreport(self,response):
        year = response.xpath('//div[@id="projektbeschreibung"]//span[contains(text(),"Final Report Year")]/following-sibling::span//text()').extract()
        abstract = response.xpath('//div[@id="projektbeschreibung"]/h4[contains(text(),"Abstract")]/following-sibling::p/text()').extract()
        print(year)
        print(abstract)