PHP代码sqlsrv_query中的错误资源（44）获取数据

Question

我在PHP中的SQL Server查询给我一个错误。

在SQL Server 13中连接并使用php 7.3

类型（SQL Server语句）的资源（44）

有人可以告诉我这个错误吗？

$servername="GABO\SQLEXPRESS";
$uid="sa";
$pwd="";
$database="GABO";
$connectionInfo=array(
    "Database"=>$database
);


$conn=sqlsrv_connect($servername,$connectionInfo);
if($conn){
    echo "Connection established.\n";
}else {
    echo "Connection could not be Establish\n";
    die(print_r(sqlsrv_errors(),true));
}
$tsql="SELECT * from TABLE_1";

$stmt=sqlsrv_query($conn,$tsql);

if($stmt){
    var_dump($stmt);
    echo "Error in statement execution.";
}else{
    die(print_r(sqlsrv_errors(),true));
}
while($row=sqlsrv_fetch_array($stmt,SQLSRV_FETCH_ASSOC)){
    echo 'some data';
}

sqlsrv_free_stmt($stmt);
sqlsrv_close($conn);