Question

我在使用功能时遇到了一些麻烦。我写了一个函数：

def dep():
  d = int(input("when did the employee depart? Please enter response in military time 0 - 2400 "))
  while (d < 0 or d > 2400):
      d= int(input("Please enter a valid number "))
return d

在以后的函数中，我想要值d。如此处所示：

def mealDep(): 
  dep = dep() 

  if dep <= 700 and dep > 0:

我现在知道我不能只调用dep（）并将其分配给变量，而是如何获取返回的值？

Answer 1

我去清理了几个错误，并使其他事情更好地实践。除了用dep = ...遮盖自己的功能外，还有其他一些事情，例如不能安全地强制转换用户输入。希望这会有所帮助。

def get_departure_time():  # verbosity is GOOD 99% of the time

    while True:
        # Get the raw input first
        departure_time = input("When did the employee depart? Please enter response in military time 0 - 2400:")

        # THEN validate. This prevents your code from breaking from type conversion
        try:
            departure_time = int(departure_time)
            assert departure_time > 0 and departure_time < 2400

            break # Breaks out of the infinite loop, and returns below

        except (ValueError, AssertionError):
            print("Please enter response in military time 0 - 2400.")
            continue

    return departure_time

def meal_dep(): #  snek_case > camelback case
    departure_time = get_departure_time() 

    if departure_time <= 700 and departure_time > 0:
        ...

如何将另一个函数返回的值调用为新函数？

1 个答案: