如何使用Xlsxwriter切片某些字符串？

Question

我的代码：

    import xlsxwriter
    from functools import partial

    def x_in_y(word, inner):
        return inner in word

    workbook = xlsxwriter.Workbook('hello.xlsx')
    worksheet = workbook.add_worksheet()

    words = [
        ('pasport','passport'),
        ('limmit','limit'),
        ('putt','put')
    ]

    sentence =['putt dweqrerwr','dfsdf putt','limmit','pasport']

    row = 0

    for wrong,correct in words:
        filtered_names = filter(partial(x_in_y, inner=wrong), sentence)
        next_elem = next(filtered_names, None)

        if next_elem:
            worksheet.write(row,0, f"Typo: {wrong} 'should be {correct}'")
            worksheet.write(row+1,0,next_elem)

        for name in filtered_names:
            worksheet.write(row+2,0,name)
        row += 2
    workbook.close()

我希望结果可以是：

错别字：pasport“应为护照”

体育

错别字：限制“应该是极限”

限制

错别字：推杆“应该放”

输入 dweqrerwrdfsdf

输入

粗体表示红色。

我希望黑体文字为红色。

但是该怎么做呢？我尝试过worksheet.write_rich_string()，但应先将文本切成薄片。

如何切片f“ {wrong}”？