我有一个从mysql数据库获取的结果数组。我想根据以下日期对这些数据进行分组：
输入数组：
$resultSet = [
0 => [
'id' => 123,
'name' => 'ABC',
'start_date' => '2019-12-18 20:00:00'
],
1 => [
'id' => 124,
'name' => 'CDE',
'start_date' => '2019-12-19 20:00:00'
],
2 => [
'id' => 125,
'name' => 'TEST',
'start_date' => '2019-12-23 20:00:00'
],
3 => [
'id' => 126,
'name' => 'BWM',
'start_date' => '2019-12-18 20:00:00'
],
4 => [
'id' => 127,
'name' => 'XYZ',
'start_date' => '2019-12-19 20:00:00'
],
5 => [
'id' => 128,
'name' => 'GHJ',
'start_date' => '2019-12-21 20:00:00'
],
6 => [
'id' => 129,
'name' => 'GHJK',
'start_date' => '2019-12-22 20:00:00'
],
7 => [
'id' => 130,
'name' => 'GHL',
'start_date' => '2019-12-20 20:00:00'
],
8 => [
'id' => 131,
'name' => 'JKL',
'start_date' => '2019-12-25 20:00:00'
]
];
输出：按过滤器显示产品组的所有列表（今天，明天，本周末，下周末等）。考虑我们在星期三运行脚本。
今天：仅显示索引记录：0、3（今天的日期：2019-12-18）
明天：仅显示索引记录：0、3（明天日期：2019-12-19）
本周末：仅显示索引记录：5、6、7（周五，周六和周日：2019-12-20、2019-12-21、2019-12-22）< / p>
下周：仅显示索引记录：2、8（日期：2019-12-23、2019-12-25）
结果将动态显示，并且每周都会显示不同的记录，如上。
使用的示例代码：
$arrayList = [];
foreach($resultSet as $element){
$arrayList[$element->start_date][] = $element;
}
dd($arrayList);
需要更改上面的代码以按照以下要求获取结果。
框架：Laravel 5.2
要求：
预期产量：
$output = [
'today' => [
0 => [
'id' => 123,
'name' => 'ABC',
'start_date' => '2019-12-18 20:00:00'
],
1 => [
'id' => 126,
'name' => 'BWM',
'start_date' => '2019-12-18 20:00:00'
]
],
'tomorrow' => [
0 => [
'id' => 124,
'name' => 'CDE',
'start_date' => '2019-12-19 20:00:00'
],
1 => [
'id' => 127,
'name' => 'XYZ',
'start_date' => '2019-12-19 20:00:00'
]
],
'this_weekend' => [
0 => [
'id' => 130,
'name' => 'GHL',
'start_date' => '2019-12-20 20:00:00'
],
1 => [
'id' => 128,
'name' => 'GHJ',
'start_date' => '2019-12-21 20:00:00'
],
2 => [
'id' => 129,
'name' => 'GHJK',
'start_date' => '2019-12-22 20:00:00'
]
],
'next_week' => [
0 => [
'id' => 125,
'name' => 'TEST',
'start_date' => '2019-12-23 20:00:00'
],
1 => [
'id' => 131,
'name' => 'JKL',
'start_date' => '2019-12-25 20:00:00'
]
]
];
我正在视图页面中运行简单的foreach循环以显示数据。如有任何疑问，请在下面发表评论。
答案 0 :(得分：1)
一开始，您应该定义一个有用的日期格式，以便进一步比较日期：
$s = new DateTime(); // create date value
$s->modify('+2 days'); // in fact today is 2019-12-16
// but you've choose 2019-12-18
// you can comment this line
//echo $s->format('Y-m-d H:i:s').PHP_EOL; // today
$today = $s->format('Ymd'); // format 20191218
echo $today.' <- today'.PHP_EOL; // today
$nextmonday = $s->modify('next monday')->format('Ymd');
echo $nextmonday.' <- next monday'.PHP_EOL.PHP_EOL; // next monday, format 20191223
然后您需要像这样循环foreach：
foreach($resultSet as $rec){
$d = date('Ymd', strtotime($rec['start_date'])); // transform to format 20191218
$d2 = date('l', strtotime($rec['start_date'])); // name of the day
echo $d.' --- '.$d2.PHP_EOL;
if ($d == $today) { // 2019-12-18 == 2019-12-18
$res['today'][] = $rec;
} else if ($d - $today == 1) { // 2019-12-19 - 2019-12-18 == 1
$res['tomorrow'][] = $rec;
} else if (in_array($d2,['Friday','Saturday','Sunday']) && $d < $nextmonday){ // < 2019-12-23 and by day name
$res['this_weekend'][] = $rec;
} else if ($d >= $nextmonday){ // next week (not a weekend)
$res['next_weekend'][] = $rec;
}
}
输出将是：
Array
(
[today] => Array
(
[0] => Array
(
[id] => 123
[name] => ABC
[start_date] => 2019-12-18 20:00:00
)
[1] => Array
(
[id] => 126
[name] => BWM
[start_date] => 2019-12-18 20:00:00
)
)
[tomorrow] => Array
(
[0] => Array
(
[id] => 124
[name] => CDE
[start_date] => 2019-12-19 20:00:00
)
[1] => Array
(
[id] => 127
[name] => XYZ
[start_date] => 2019-12-19 20:00:00
)
)
[next_weekend] => Array
(
[0] => Array
(
[id] => 125
[name] => TEST
[start_date] => 2019-12-23 20:00:00
)
[1] => Array
(
[id] => 131
[name] => JKL
[start_date] => 2019-12-25 20:00:00
)
)
[this_weekend] => Array
(
[0] => Array
(
[id] => 128
[name] => GHJ
[start_date] => 2019-12-21 20:00:00
)
[1] => Array
(
[id] => 129
[name] => GHJK
[start_date] => 2019-12-22 20:00:00
)
[2] => Array
(
[id] => 130
[name] => GHL
[start_date] => 2019-12-20 20:00:00
)
)
)
注意： 最后一个名为 next_weekend 的数组，也许您需要将其重命名为 next_week < em>，因为它的日期刚好在您当前的周末之后。
我认为您已经理解了一个主意，并且可以添加进一步的逻辑。
答案 1 :(得分：0)
尝试下面的示例
$group = [];
foreach ($start_date as $item) {
if (!isset($group[$item['start_date']])) {
$group[$item['start_date']] = [];
}
foreach ($item as $key => $value) {
if ($key == 'start_date') continue;
$group[$item['start_date']][$key] = $value;
}
}
答案 2 :(得分：0)
我认为您应该设置一系列不同的日期：今天，明天，本周末，下周
检查链接以获取时间格式：https://carbon.nesbot.com/docs/
$now = Carbon::now();
echo $now; // 2019-11-20 16:41:03
echo "\n";
$today = Carbon::today();
echo $today; // 2019-11-20 00:00:00
echo "\n";
$tomorrow = Carbon::tomorrow('Europe/London');
echo $tomorrow; // 2019-11-21 00:00:00
echo "\n";
通过比较日期条件检查结果并创建数组并将其组合为一个数组。
$totalarr = array('today'=>$todayarr,'tomorrow'=>$tomorrowarr,'thisweek'=>$thisweek,'nextweek'=>$nextweekarr);
print_r($totalarr);
答案 3 :(得分：0)
好吧，如果您使用的是laravel，那么您可以利用碳的力量和收集方法来解决此类问题。
您可以映射阵列键并使用carbon方法对其进行分组。检查以下代码片段将为您提供准确的结果。
$output = collect($resultSet)->map(function ($value) {
$group_by_key = Carbon::parse($value['start_date']);
switch ($group_by_key) {
case $group_by_key->isToday():
$group_by_key = 'today';
break;
case $group_by_key->isTomorrow():
$group_by_key = 'tomorrow';
break;
case $group_by_key->isWeekend():
$group_by_key = 'this_weekend';
break;
case $group_by_key->isNextWeek():
$group_by_key = 'next_week';
break;
default:
$group_by_key = $group_by_key->format('l');;
break;
}
$value['group_by_key'] = $group_by_key;
return $value;
})->groupBy('group_by_key');
var_dump($output);