Question

我正在尝试使代码更高效。目前，我确实有两个函数在while循环内基本相同。仅主题（a和b）不同。这两个主题每个循环都在轮换。

到目前为止，这是我的框架：

#run engine
engine_running = True

#set first subject
a = True
b = False

# while engine is running rotate between a and b
while engine_running == True:
       if (a == True):
             Function_a()
             a = False
             b = True
       elif (b == True):
             Function_b()
             a = True
             b = False
       else:
             print('Error')

这是两个功能的框架。值得注意的是，每个函数都读取同一组数据，其中包含a和b的数据。

def Function_a():
       import Data
       import random

       # Get Data and the weights
       List = [Data.a_person1, Data.a_person2, Data.a_person3]
       Weight = [List[0]['attribute'],List[1]['attribute'], List[2]['attribute']

       # Choosing a random person based on its attribute
       Selection = random.choices(List,Weight)
       print(Selection[0]['name'], 'has been chosen')

def Function_b():
       import Data
       import random

       # Get Data and the weights
       List = [Data.b_person1, Data.b_person2, Data.b_person3]
       Weight = [List[0]['attribute'],List[1]['attribute'], List[2]['attribute']

       # Choosing a random person based on its attribute
       Selection = random.choices(List,Weight)
       print(Selection[0]['name'], 'has been chosen')

我是python的新手，所以我知道这看起来很难看，并且可能有更好，更有效的方法。目前，它对我有效。但是也许你有一些建议给我？

Answer 1

您可以简单地将要处理的列表传递给该功能

<activity android:name=".MainActivity">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
 </activity>
 <activity android:name=".SplashScreenActivity" />

Answer 2

def a():
    print("a")

def b():
    print("b")

switch = True
while True:
    if switch:
        a()
        switch = False
    elif not swith:
        b()
        switch = True
    else:
        print('Error')

对不同变量执行相同功能的有效方法

2 个答案: