使用where子句中的子查询的内部联接对表进行排序不起作用

Question

我有如下原始SQL查询

 select feed_items.feed_item_id, title 
from feed_items 
inner join tags 
on feed_items.feed_item_id = tags.feed_item_id 
where (select symbol from symbol_name_rules where name = 'apple')= any(tags) 
order by pubdate desc limit 5;

效果很好，我正在尝试使用sequelize重写它，这一直给我一个错误

models.FeedItem.findAll({
    attributes: [
      'feedItemId',
      'Tag.tags'
    ],
    order: [['pubdate', 'DESC']],
    include: [{ model: models.Tag, attributes: [] }],
    limit: 50,
    logging: console.log,
    raw: true,
    where: {
        [models.Sequelize.Op.and]: [models.sequelize.literal('SELECT symbol FROM symbol_name_rules WHERE name="apple"=ANY(tags)')]
    }
}).then(console.log)

它一直给我这个错误未处理的拒绝SequelizeDatabaseError：语法错误位于“ =”或附近

任何人都可以建议如何解决此问题