KSoap soapEnvelope bodyIn和getResponse()问题

时间:2011-05-09 09:10:15

标签: android web-services ksoap2 getresponse

我使用以下代码通过soap调用方法。它工作得很好。

private static final String SOAP_ACTION = "http://tempuri.org/GetAuthenticateUser";
    private static final String METHOD_NAME = "GetAuthenticateUser";
    private static final String NAMESPACE = "http://tempuri.org/";
    private static final String URL = "http://stage.mysite.com/FinancialSnapshotService/Service.asmx?WSDL";
   // I have tried http://stage.mysite.com/FinancialSnapshotService/Service.asmx also

    public void getResults() {

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
        request.addProperty("vstrUserID", "vk@gmail.com");
        request.addProperty("vstrPassword", "password");

        SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(
                    SoapEnvelope.VER11);
        soapEnvelope.dotNet = true;
        soapEnvelope.setOutputSoapObject(request);


        HttpTransportSE aht = new HttpTransportSE(URL);

        try {
            aht.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
            aht.call(SOAP_ACTION, soapEnvelope);

            SoapObject result = (SoapObject) soapEnvelope.getResponse();


            Log.d("WS", String.valueOf(result));
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

但是当我尝试在同一服务器中的某些其他方法中使用相同的代码时,它会给出ClassCastException: org.ksoap2.SoapFault。如果我将行SoapObject result = (SoapObject) soapEnvelope.getResponse();更改为SoapObject result = (SoapObject)soapEnvelope.bodyIn;,则效果非常好。任何人都可以告诉我这段代码的基本内容,在哪里使用bodyIn以及在哪里使用getResponse()

2 个答案:

答案 0 :(得分:2)

我使用以下代码来解决这个问题

try{
                result = (SoapObject) soapEnvelope.getResponse();
            }catch (ClassCastException e) {
                result = (SoapObject)soapEnvelope.bodyIn; 
            }

但我仍然不清楚为什么会这样。

答案 1 :(得分:0)

如果你去那里,你会看到身体没有被序列化,而得到respose给你soapobject已经加强了。是我的承诺,如果我错了,我很抱歉。 http://ksoap2.sourceforge.net/doc/api/org/ksoap2/SoapEnvelope.html#bodyIn

我有同样的问题,因为我的网络服务正在给我html,如果是你的问题,我建议你在网络服务端编码anser。

添加try和catch

catch (SoapFault e) { SoapObject result = soapEnvelope.BodyIn; }