Question

        # This is a guess the number game.
        import random

        print ('Hello, What is your name?')
        name = input()

        print('Well, ' + name + '! I am thinking of a number between 1 to 20.') 
        secretNumber = random.randint(1,20)
        print('Debug:' + str(secretNumber))

        for guessTaken in range (1,7):
            print('Take a guess. '+ name +'!' )
            guess =int(input())


            if guess<secretNumber:
                print('Your guess is too low')
            elif guess>secretNumber:
                print('Your guess is too high')
            else:
                break # This is for correct guess is equal.

        if guess ==secretNumber:
            print('Good Job, ' +name+ '! You guess my number in ' + str(guessTaken)+ ' guesses!')
        else:
            print('Nope, The number I was thinking of was ' +str(secretNumber))

嗨，我的超级编码员，

所以我试图将Try and Except块放到该程序中，我尝试将它放到后面不幸的是，guess = int（input（））无法使它正常工作。

因此，我正在尝试处理ValueError，因此，可以说用户需要输入Integers（数字），如果他键入诸如“ One”，“ Six”之类的字符串，则程序将崩溃。我想处理这种情况。请帮我一下。：）

非常感谢。眼镜蛇

Answer 1

如何处理，它再次询问用户是否输入了字符串：

        # This is a guess the number game.
        import random

        print ('Hello, What is your name?')
        name = input()

        print('Well, ' + name + '! I am thinking of a number between 1 to 20.') 
        secretNumber = random.randint(1,20)
        print('Debug:' + str(secretNumber))

        for guessTaken in range (1,7):
            print('Take a guess. '+ name +'!' )
            try:
               guess =int(input())
            except:
               print("Must be a number, try again: ")
               continue

            if guess<secretNumber:
                print('Your guess is too low')
            elif guess>secretNumber:
                print('Your guess is too high')
            else:
                break # This is for correct guess is equal.

        if guess ==secretNumber:
            print('Good Job, ' +name+ '! You guess my number in ' + str(guessTaken)+ ' guesses!')
        else:
            print('Nope, The number I was thinking of was ' +str(secretNumber))

Answer 2

如果用户输入的不是数字，则python会由于出现错误而跳至异常，因此我在印刷品中添加了一些文字以阐明游戏规则。我在for循环之后使用else，这在用户无法猜测7次尝试中的数字的情况下有时非常有用，您可以对其进行测试，看看即使else不在if之后，当ifgues == secretNumber时是正确的，并且您中断了循环，else语句不执行任何操作。 P.S仍然是在这里回答的新问题，请提供有关我的回答的反馈

import random

print ('Hello, What is your name?')
name = input()

print('Well, ' + name + '! I am thinking of a number between 1 to 20.') 
secretNumber = random.randint(1,20)
print('Debug:' + str(secretNumber))

for guessTaken in range (1,7):
    print('Take a guess. '+ name +'!, You Have 7 tries'  )
    try:
        guess = int(input())
        if guess<secretNumber :
            print('Your guess is too low')
        elif guess>secretNumber : 
            print('Your guess is too high')
        if guess == secretNumber:
            print('Good Job, ' + name + '! You guess my number in ' + str(guessTaken)+ ' guesses!')
            break # This is for correct guess is equal.
    except:
        print('Please Enter A number ' + name + 'and not anything else' )


else:
    print('Nope, The number I was thinking of was ' +str(secretNumber))

我应该如何在Try循环中添加“尝试＆阻止”来处理

2 个答案: