Question

我使用的是自定义用户模型，当我尝试在其他模型中引用它时，出现错误。

[v24x,v24y]

views.py

Exception Value:    
NOT NULL constraint failed: send_appdata.product_id_id

models.py

from django.contrib.auth import get_user_model
AppOnboarding = get_user_model()
# get data from json
@api_view(['POST'])
def index(request):
    product_id = AppOnboarding.objects.get(pk=request.data['product_id'])

    product_name = request.data['product_name']
    product_url = request.data['product_url']
    subject = request.data['subject']
    body = request.data['body']
    recipient_list = request.data['recipient_list']
    sender_mail = request.data['sender_mail']
    email_type = request.data['email_type']
    broadcast_mail = request.data['broadcast_mail']
    email_status = status.HTTP_200_OK
    location = request.data['location']
    # make an object of AppData
    app_data = AppData(product_id=product_id, product_name=product_name, product_url=product_url,
                       subject=subject, body=body, recipient_list=recipient_list, sender_mail=sender_mail, email_type=email_type, broadcast_mail=broadcast_mail, email_status=email_status, location=location)
    # save it to DB
    app_data.save()

AppOnboarding是另一个应用程序中的自定义用户模型。

我探讨了类似的问题，但无法解决问题。我们非常感谢您的帮助。

Answer 1

最近（在其余模型字段之后）添加了此外键product_id吗？如果是，则需要将其设置为可为空（null = True），然后运行makemigrations，然后运行migrate

Answer 2

发现错误，当我使用python shell手动检查时，Apponboarding.objects.get（id = 1）返回不退出但Apponboarding.objects.get（id = 2）和其他返回了电子邮件地址而不是ID。尚不清楚ID如何从2而不是1开始（因为它是自动字段），以及为什么返回电子邮件而不是ID的原因。

Answer 3

product_id = models.ForeignKey(AppOnboarding, on_delete=models.PROTECT)

应该是

product = models.ForeignKey(AppOnboarding, on_delete=models.PROTECT)

异常值：NOT NULL约束失败：send_appdata.product_id_id

3 个答案: