根据从python中的点输入列表生成的点集合创建（相同点）列表

Question

更好地举例说明问题：

提供输入list1和list2 ：

list1 = [0,1,2,3,4]
list2 = [[0,1],[1],[2,3],[2],[4]]

    list1[0] = 0 --> [0,1] of list2[0] (meaning that  element 0 of list1 is mapped to element 0 and 1 of list2)
    list1[1] = 1 --> [1] of list2[1]   (meaning that  element 1 is mapped to element 1)
    list1[2] = 2 --> [2,3] of list2[2] (meaning that  element 2 is mapped to element 2 and 3)
    list1[3] = 3 --> [2] of list2[3]   (meaning that  element 3 is mapped to element 2)
    list1[4] = 4 --> [4] of list2[4]   (meaning that  element 4 is mapped to element 4 itself)

所以，我想从list1和list2像这样列出：

outputlist=
[  [[0], [0]], 
   [[1], [0]], 
   [[2], [2]], 
   [[3], [2]],
   [[4], [4]]
]

    outputlist shows that:
    1st element is identical to itself
    2nd element is identical to first element
    3rd element is identical to itself
    4th element is identical to 3rd element
    5th element is identical to itself

基本上，这是一个映射，显示list1的哪些元素相同。