**您好,当我尝试点击邮递员的post api时,我收到了API的响应,但未收到邮递员的请求
当我打印请求时显示但不显示数据
我附上了邮递员的屏幕截图
**
from django.shortcuts import render
from django.http import HttpResponse
from django.core.mail import send_mail
from django.views.decorators.csrf import csrf_exempt
# Create your views here.
@csrf_exempt
def email(request):
print(request)
subject = request.POST.get('subject', 'hello')
body = request.POST.get('body', 'very bad')
senderEmail = request.POST.get('senderEmail', 'my_email@gmail.com')
send_mail(subject, body, 'sender@gmail.com', [senderEmail], fail_silently=False)
return HttpResponse("Email Send.")
答案 0 :(得分:0)
我不确定您的项目的上下文是什么,但是您可以使用序列化程序并编写类似以下内容的内容:return Response(serializer.initial_data, status=status.HTTP_200_OK)
。 serializer.initial_data
将是您最初发送的数据,并将显示在Postman响应框中。希望这可以帮助。 (您可以了解有关Django here的序列化程序的更多信息。)
答案 1 :(得分:0)
在python代码中,您可以如下更改代码:
@api_view(['POST'])
@csrf_exempt
def email(request):
formDataReceved = request.POST
subjectReceived = formDataReceved['subject'].strip()
bodyReceived = formDataReceved['body'].strip()
senderEmailReceived = formDataReceved['senderEmail'].strip()
send_mail(subjectReceived, bodyReceived, 'sender@gmail.com', [senderEmailReceived], fail_silently=False)
return HttpResponse("Email Send.")